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masya89 [10]
3 years ago
6

If p + 2q = 20, what is the value of 101p + 202q?

Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

bhvigjcgujj

Step-by-step explanation:

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HELP!!! Due in 10 mins help me pls! WILL GIVE BRAINLIEST!!!
Vadim26 [7]

Answer:

1234567890

Step-by-step explanation:

Each of the digits is divisible by their individual index in the number. Adding a 0 at the ends allows for the number to be divisible by 10 and completes the 10 digit requirement.

3 0
3 years ago
Read 2 more answers
How to substitute 3x+3y=-3 and y=5x-1?
schepotkina [342]
Since y = 5x-1, we can fill it into 3x + 3y = -3. First, let's look at relating to a simpler equation. Let's say that x + y = 9 and y = 3 + 5. Now, we can fill it in to get that x + (3 + 5) = 9. Now, we know that 3+5 is 8, so x + 8 = 9. Now, x = 1. Likewise, we can do the same. For 3x + 3y = -3, all we need to do is to switch the y in 3x + 3y = -3 with 5x - 1. So it would become 3x + 3(5x - 1) = -3. Now we distribute to get 3x + 15x - 3 = -3. Now add three to both sides to get 3x + 15x = 0. Now simplify to get 18x = 0. Now we know that x = 0. Now fill x into y = 5x - 1. So y = 5(0) - 1. Now we know that y = -1.

To check fill in the answer to 3x + 3y = -3.
3(0) + 3(-1) = -3
 0 + (-3) = -3
0 - 3 = -3
-3 = -3
Now that our check is completed we now know that x is 0 and y is -1.
7 0
3 years ago
The temperature decreases by 0.5 degrees every hour.
UNO [17]

i think its the 2nd or 1st one

rlly tried here!

8 0
3 years ago
Can someone be so freaking awesome and help me out with the correct answer please :( !?!?!?!?!???!!! 30 points!!!
Sindrei [870]

\bf 7~~,~~\stackrel{7+6}{13}~~,~~\stackrel{13+6}{19}~~,~~\stackrel{19+6}{25}\qquad \impliedby \qquad \textit{common difference "d" is 6}

we know all it's doing is adding 6 over again to each term to get the next one, so then

\bf \stackrel{\textit{Recursive Formula}}{\stackrel{\textit{nth term}}{f(n)}~~=~~\stackrel{\textit{the term before it}}{f(n-1)}~~~~\stackrel{\textit{plus 6}}{+~~~~6}}

now for the explicit one

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=7\\ d=6 \end{cases} \\\\\\ a_n=7+(n-1)6\implies a_n=7+6n-6\implies \stackrel{\textit{Explicit Formula}}{\stackrel{f(n)}{a_n}=6n+1} \\\\\\ therefore\qquad \qquad f(10)=6(10)+1\implies f(10)=61

3 0
3 years ago
HELPP ASAP!!<br> WHats the area?
Ira Lisetskai [31]

the answer should be 24 because you can divide it into 2 shapes and solve them separately and add those products

3 0
3 years ago
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