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3 years ago

12

Find the slope of the line that passes through (2, 5) and (2,2 ) WORTH 20 POINTS

1 answer:

mixas84 [53]3 years ago

4 0

Pls mark brainlessness please

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Find the oth term of the geometric sequence 9, -18, 36, ...

Sphinxa [80]

Answer:

2304

Step-by-step explanation:

<u>Given :- </u>

A geometric sequence is given to us which is 9 , -18 , 36.

And we need to find out the 9th term of the sequence. Here firstly we should find the Common Ratio and then we can substitute the respective values in the formula to find the nth term of a geometric sequence .

<u>Common Ratio :- </u>

$:\implies$ CR = -18÷ 9 = -2

<u>The </u><u>9</u><u> th term :- </u>

$:\implies$ T_n = arⁿ - ¹

$:\implies$ T_9 = 9× (-2) ⁹ - ¹

$:\implies$ T_9 = 9 × (-2)⁸

$:\implies$ T_9 = 9 × 256

$:\implies$ T_9 = 2304

<u>Hence the 10th term is </u><u>2</u><u>3</u><u>0</u><u>4</u><u>.</u>

3 0

3 years ago

A dealer paid $7,000 for a car at an auction. At the dealership, a salesperson sold the car for 30% more than the auction price.

timurjin [86]

30% of $7000 is $2100
25% of $2100 is $525

7 0

3 years ago

(x²+4x+4)/(x+2)<br>algebraic expressions class 8<br>no spamms

maks197457 [2]

Answer:

x+2

Step-by-step explanation:

$\frac{x ^{2} + 4x + 4 }{x + 2} \\ \frac{(x) ^{2} + 2 \times x \times 2 + (2) ^{2} }{x + 2} \\ \ \frac{(x + 2) ^{2} }{x + 2} \\ \frac{(x + 2)(x + 2)}{x + 2} \\ x + 2$

5 0

2 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago

HELP WITH THIS QUESTION, ASAP!!

alukav5142 [94]

The answer to that question is b

6 0

3 years ago