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Anestetic [448]
3 years ago
8

Help please I will mark brainliest

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0
40° snnsdndnxnnxndndndnndndndndndjdjjd
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Mark ran 875 miles in the track club this year . Mark ran in 52 track meets and ran the same number of miles in each . how many
dmitriy555 [2]

Answer:

16\frac{43}{52}

Step-by-step explanation:

875/52 = 16\frac{43}{52}

8 0
3 years ago
Casey bought 6 bags of apples. Each bag contained 5 apples. How many
Snezhnost [94]
30 apples bc 5x6 (5 six times) =30
7 0
3 years ago
Given f(x)=6x+4 and g(x)=3x+7 then what is f(g(1))
iren [92.7K]
10 is the best answer
8 0
3 years ago
There are 15 candidates for 4 job positions.
Veronika [31]

Answer:

32760 ways

Step-by-step explanation:

Given

Number of Candidates = 15

Job Positions = 4

Required:

Number of outcomes

This question represent selection; i.e. selecting candidates for job positions;

This question can be solved in any of the following two ways

Method 1.

The first candidate can be chosen from any of the 15 candidates

The second candidate can be chosen from any of the remaining 14 candidates

The third candidate can be chosen from any of the remaining 13 candidates

The fourth candidate can be chosen from any of the remaining 12 candidates

Total Possible Selection = 15 * 14 * 13 * 12

<em>Total Possible Selection = 32760 ways</em>

<em></em>

Method 2:

This can be solved using permutation method which goes thus;

nPr = \frac{n!}{(n-r)!}

Where n = 15 and r = 4

So;

nPr = \frac{n!}{(n-r)!} becomes

15P4 = \frac{15!}{(15-4)!}

15P4 = \frac{15!}{11!}

15P4 = \frac{15*14*13*12*11!}{11!}

15P4 = 15*14*13*12

15C4 = 32760

<em>Hence, there are 32760 ways</em>

8 0
3 years ago
A six-week fitness program was designed to decrease the time it takes retired individuals to walk one mile. At the beginning of
valkas [14]

Answer:

c. The sampling distribution of the sample means can be assumed to be approximately normal because the distribution of the sample data is not skewed

Step-by-step explanation:

From the given data, we have;

The category of the sample = Retired individuals

The number of participants in the sample = 20

The duration of program = six-weeks

The improvement seen by most participants = Little to no improvement

The improvement seen by few participants = Drastic improvement

Therefore, given that the participants are randomly selected and the majority of the participants make the same observation of improvement in the time to walk a mile, we have that, the majority of the outcomes show little difference in walk times after the program, therefore, the distribution of the sample data is not skewed and can be assumed to be approximately normal

7 0
3 years ago
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