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galina1969 [7]
2 years ago
10

How do I solve this?​

Mathematics
1 answer:
Scorpion4ik [409]2 years ago
7 0

the answer would be B ( 4,-5) because when I put them on a graph it came up with the right one

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For what value of x will the line passing through the following pairs of points be
Romashka [77]
The answer is g(x)= 5x- 19
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2 years ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

8 0
1 year ago
Can I Get Help On This Question?
Gnoma [55]

I believe it would just be -1

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Match the STATEMENTS with the reasons that are given for the following proof. Note that these reasons would be listed on the rig
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Answer:


Step-by-step explanation:

1.  AB||DC and AB = CD             Given

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3 .AC = AC                                 Reflexive

4. ΔABC ≅ ΔCDA                      SAS

5.  ∠2 = ∠3                                CPCTE

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3 years ago
Write an equation which has 8 as its solution.
Allisa [31]

Answer:

look at the picture i sent......

3 0
3 years ago
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