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fredd [130]
3 years ago
13

If a cubic foot of stone weighs 150 lb and a cubic foot of iron weighs 480 lb, what fraction of the second weight is the first o

ne?
Mathematics
2 answers:
iris [78.8K]3 years ago
8 0

Answer:

72,000

Step-by-step explanation:

AVprozaik [17]3 years ago
5 0

this should help you

mark me brainliest

just press the blue link

Download pdf
You might be interested in
Which number is missing from the following prime factorization expression? 792 = __ x 2 x 2 x 2 x 3 x 11 A. 2 B. 3 C. 5 D. 7
lions [1.4K]

Answer:

3

Step-by-step explanation:

Evaluate 2 x 2 x 2 x 3 x 11 (better written as 2·2·2·3·11, because "x" is a variable name, not a math operator).

2·2·2·3·11 = 8·33 = 264

Then divide 792 by this 264 to find the final factor:

final factor = 792/264 = 3

Then the prime factorization of 792 is 2·2·2·3·3·11

which we obtained by multiplying 2 x 2 x 2 x 3 x 11 by 3.

7 0
3 years ago
Read 2 more answers
PLEASE HELP!!<br> Solve.<br><br> 5=15x−3<br><br> Enter your answer in the box.<br><br> x=
patriot [66]

x = 1/120

i did not see the comment about the 1/5 until now

hope this helps

3 0
3 years ago
A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weig
jenyasd209 [6]

Answer:

z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625    

The p value for this case would be given by:

p_v =P(z  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

Step-by-step explanation:

Information provided

\bar X=19.87 represent the sample mean

\sigma=0.4 represent the population deviation

n=25 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:  

Null hypothesis:\mu \geq 20  

Alternative hypothesis:\mu < 20  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing the info given we got:

z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625    

The p value for this case would be given by:

p_v =P(z  

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

7 0
3 years ago
What is the answer 4.6n+7.1n+12.8n-1.6n= ?
Alex787 [66]
The answer would be=22.9n
4 0
3 years ago
Factor x^2+3xy+2y^2+4x+7y+3
Aleksandr-060686 [28]
3xy(x+4)(2y+7)(xy+1) is what I got
4 0
3 years ago
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