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2 years ago

If julie make 18 baskets how many baskets does kari make how many baskets do they make in all

Mathematics

1 answer:

melisa1 [442]2 years ago

3 0

Answer:

18x

Step-by-step explanation:

j=18

k=x

18xor18

I do not understand this question

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What is the answer to -4.3g=25.8

8090 [49]

G=-6
You just divide both sides by -4.3

7 0

3 years ago

How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP

NNADVOKAT [17]

<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 × $10^{-2}$ .

To find, the number of times smaller is 2 × $10^{-3}$ than 4 × $10^{-2}$ = ?

∴ x = $\dfrac{4\times 10^{-2}}{2\times 10^{-3}}$

= 2 × $10^{-2}$ × $10^{3}$

Using the identity,

$a^{m}=\dfrac{1}{a^{-m}}$

= 2 × $10^{-2+3}$

Using the identity,

$a^{m} \timesa^{n}=a^{m+n}$

= 2 × $10^{1}$

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

6 0

3 years ago

GIVING OUT BRAINLIEST HELP ME PLSSS

Keith_Richards [23]

Answer:

0.7880

Step-by-step explanation:

5 0

3 years ago

If a family spend $840 in a year on rent how much do they spend in a manth

dalvyx [7]

Month*
divide 840 with 12
as 1 year has 12 months
and you get 70$

so the family spends $70 every month

4 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is </u></em>

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago