To solve this, you can create an equation. Say the weight of Umbar is x, then Saira weighs x+25. Together they weigh 205. So, you get the equation
x+x+25=205
Then solve for x.
2x+25=205
2x=180
x=90
Then to find Saira's weight, add 25 to Umbar's weight.
90+25=115.
Answer:
Y=-3/2x-4
Step-by-step explanation:
Point slope form is
y=mx+b
mx is the slope
and b is the y-intercept
Pennies (P) = 24
Nickels = 1/2P
Dimes = 1/2P + 5
Quarters = (1/2P + 5) -6
Therefore...
Nickels = 1/2P = 1/2(24)= 12
Dimes = 12 + 5 = 17
Quarters = 17 - 6 = 11
Answer:
The length of river frontage for each lot are 96.55 ft. 98.85 ft, 101.15 ft and 103.45 ft.
Step-by-step explanation:
See the attached diagram.
The river frontage of 400 ft will be divided into 84 : 86 : 88 : 90 for each lot as AP, BQ, CR, DS and ET all are parallel.
Therefore, PQ : QR : RS : ST = 84 : 86 : 88 : 90 = 42 : 43 : 44 : 45
Let, PQ = 42x, QR = 43x, RS = 44x and ST = 45x
So, (42x + 43x + 44x + 45x) = 400
⇒ 175x = 400
⇒ x = 2.2988.
So, PQ = 42x = 96.55 ft.
QR = 43x = 98.85 ft.
RS = 44x = 101.15 ft and
ST = 45x = 103.45 ft
(Answer)