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2 years ago

PLEASE HELP ME ASAP I NEED HELP ITS DUE AT 11:59

Mathematics

1 answer:

ivanzaharov [21]2 years ago

8 0

Answer:

When -8 is x then y = -29

When -4 is x then y = -17

When 4 is x then y = 7

When 6 is x then y = 13

Step-by-step explanation:

You simply substitute the numbers on the x row for x in the equation, then you solve the problem. (3 x -8) - 5, ect.

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Pls answer ASAP I need help

gavmur [86]

Answer:

g=1.5

Step-by-step explanation:

-0.4+0.9=0.5

0.5*3 1.5

6 0

3 years ago

Find the measurements of each angle

Lana71 [14]

GED is 43
CEB and AED is 90
GEB and FEA is 47

hope this helps!

4 0

2 years ago

Read 2 more answers

What is the interquartile range (IQR) of the following data set?

OleMash [197]

Answer:

Step-by-step explanation:

Arrange data set

19, 4, 17, 3, 6, 5,5, 3, 11, 12, 3, 7, 15, 8, 8, 10,5, 3, 12, 41, 36

in ascending order

3, 3, 3, 3, <u>4, 5,</u> 5, 5, 6, 7, 8, 8, 10, 11, 12, <u>12, 15,</u> 17, 19, 36, 41

The median is $Q_2=8$

$Q_1=\dfrac{4+5}{2}=4.5$

$Q_3=\dfrac{12+15}{2}=13.5$

Thus, the interquartile range is

$Q_3-Q_1=13.5-4.5=9$

4 0

3 years ago

Which of the following conditions must be met to conduct a two-proportion significance

katrin [286]

Hello, I Am BrotherEye

Answer: C.) 111 Only

Step-by-step explanation:

7 0

2 years ago

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

Dimas [21]

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

Acute angle have measure less than 90°

Now given as :

$sin(\frac{x}{2} + 2x)$ = $cos(2x +\frac{3x}{2})$

Or, $cos(90° - (\frac{x}{2}+2x))$ = $cos(2x +\frac{3x}{2})$

SO, $(90° - (\frac{x}{2}+2x))$ = $2x+\frac{3x}{2}$

Or, 90° = $2x+\frac{3x}{2}$ + $\frac{x}{2}+2x$

or, 90° = $\frac{4x}{2}$ + 4x

Or, 90° = $\frac{12x}{2}$

So, x = $\frac{90}{6}$ = 15°

∴ $sin(\frac{x}{2} + 2x)$ = $sin(\frac{15}{2} + 30)$

So, $sin(\frac{x}{2} + 2x)$ = sin $\frac{75}{2}$

∴ The value of Ф_1 = $\frac{75}{2}$ = 37.5°

Similarly $cos(2x +\frac{3x}{2})$ = $cos(30 +\frac{45}{2})$

So ,The value of Ф_2 = $\frac{105}{2}$ = 52.5°

∵ β α

So, As 37.5°52.5°

∴ β = 37.5°

Hence From given relation the value of β is 37.5° Answer

7 0

3 years ago