Hello! My name is Chris and I’ll be helping you with this problem.
Date: 9/27/20 Time:
Answer:
x = -1
Explanation:
Step 1: Simplify both sides of the equation.
−2(x+3)=−4(x+1)−4
(−2)(x)+(−2)(3)=(−4)(x)+(−4)(1)+−4(Distribute)
−2x+−6=−4x+−4+−4
−2x−6=(−4x)+(−4+−4)(Combine Like Terms)
−2x−6=−4x+−8
−2x−6=−4x−8
Step 2: Add 4x to both sides.
−2x−6+4x=−4x−8+4x
2x−6=−8
Step 3: Add 6 to both sides.
2x−6+6=−8+6
2x=−2
Step 4: Divide both sides by 2.
2x = -2
/2 /2
x=−1
I hope this helped answer your question! Have a great rest of your day!
Furthermore,
Chris
Answer:
6 + (d * 2)
Step-by-step explanation:
You are adding 6 to the equation after the amount d times 2. In that case, a parentheses is required to round up d * 2.
Answer:
.83
Step-by-step explanation:
If you take 100 shows 60 shows got favorable response and in that 50 shows were successful.
So probability for a show to be successful if it got a favorable response is = 50/60 = 0.83
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
(2,0) and (-1/2,0) is the correct answer
