Answer:
- m∠ABP is 32°,
- m∠ABC is 64°.
Step-by-step explanation:
According to the construction we have:
- BD = BE
- PD = PE
- BP - is common side of triangles BPD and BPE
It gives us:
Then, corresponding angles of congruent triangles are congruent:
So,
- ∠ABP ≅ ∠CBP ⇒ m∠ABP = 32°
Then,
- m∠ABC = m∠ABP + m∠CBP = 32° + 32° = 64°
Answer:
- cylinder — 90π in³
- pyramid — 37 1/3 in³
- cone — 12.5π in³
Step-by-step explanation:
The volume of a cylinder is given by ...
V = Bh . . . . . where B is the base area and h is the height
The volume of a pyramid or cone is given by ...
V = (1/3)Bh . . . . . where B is the base area and h is the height
The area of a square of side length s is ...
A = s²
The area of a circle of radius r is ...
A = πr²
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Using these formulas, the volumes of these objects are ...
cylinder: (9π in²)(10 in) = 90π in³
square pyramid: (1/3)(4 in)²(7 in) = 37 1/3 in³
cone: (1/3)(π(2.5 in)²)(6 in) = 12.5π in³ . . . . slightly larger than the pyramid
Answer:
A
Step-by-step explanation:
Answer:
10 units
Step-by-step explanation:
Let the shortest side be x
Now since we are given that The congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle.
So, the length of the congruent sides (each) = x+1
Thus the perimeter of triangle = sum of all sides
= x+x+1+x+1
=3x+2
Now we are given that The perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle.
Side of square = x-2
So, perimeter of square = 4*side
=4(x-2)
=4x-8
Now since the perimeter of the triangle and square are equal
So,

Hence the shortest side of the triangle is 10 units.