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fenix001 [56]
3 years ago
7

Find the length of side

Mathematics
2 answers:
DochEvi [55]3 years ago
7 0

Answer:

2

Step-by-step explanation:

Pythagoras. c² = a² + b²

since both "side angles" are equal (45 degrees), we know it is an isosceles triangle, that means also the other side = x.

and so,

8 = x² + x² = 2x²

4 = x²

x = 2

omeli [17]3 years ago
3 0

Answer:

x = 2

Step-by-step explanation:

sin(45)/x = sin(90)/\sqrt{8}

\sin \left(45^{\circ \:}\right)=\frac{\sqrt{2}}{2}

x = \sqrt{8} \sin \left(45^{\circ \:}\right)

x = \sqrt{8}  \frac{\sqrt{2}}{2}

x = \frac{\sqrt{16}  }{2}

x = 4/2

x = 2

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Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
Read 2 more answers
100 points + brainlest please help due today
Reptile [31]

Answer:

Use the formula for direct variation

Step-by-step explanation:

6 0
3 years ago
If the dimensions of a circle are tripled, the area of the resulting circle will also be three times larger.
Arturiano [62]

Answer:

the answer in false

Step-by-step explanation:


8 0
3 years ago
Which numbers are necessary to solve this problem?
Bad White [126]
Hello there.

<span>Which numbers are necessary to solve this problem? 

Brian goes to the gym 3 times a week. He exercises for 45 minutes each visit. Fifteen of those minutes are spent on weights and the rest are spent on the treadmill. 

How much time does Brian spend on the treadmill in 4 weeks?

Answer: </span><span>3 times a week, 45 minutes, 15 minutes, 4 weeks
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5 0
3 years ago
Read 2 more answers
Is 10-2x is less then 10 what is x
nignag [31]
The answer is: Yes 10-2x is less than 10, x= -5
3 0
3 years ago
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