Answer:
- <u>The farmer bought 170 animals of each species</u>.
Step-by-step explanation:
The translation of the question into English is:
<em>"a farmer bought the same number of calves and cows for 476,000. He/she paid 800 for a calf and 2000 for a cow, how many animals of each species did he/she buy?"</em>
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<h2>Solution to the problem</h2>
<u>1. Choose the variable's name and translate the verbal statements into algebraic expressions:</u>
- a) number of calves or cows: x
- b) He/she paid 800 for a calf: 800x
- c) He/she paid 2,000 for a cow: 2000x
- d) For 476,00: 800x + 2000x = 476,000 . . . . this is your equation
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<u>2. Solve the equation:</u>
<u>a) Write the equation:</u>

<u>b) Add like terms:</u>

<u>c) Use division property of equalities: divide both sides by 800:</u>

<u>d) Translate the solution into a verbal statement:</u>
Since x represents both the number of calves and the number of cows, the answer is:
- <u>The farmer bought 170 animals of each species</u>.
H = 60M
I think this is what u need
Answer:
Step-by-step explanation:
Number of students in her class = x students
x is 2 more than a multiple of 4
This means x is an even number because multiples of 4 are even and adding 2 does not change its parity.
X is also 1 more than a multiple of 5. And we know x is and even number it has to be a multiple of 5 ending in 5, not 0. So 5 + 1 is 6.
All multiples of 4 ending in six are 16, 36, 56 ..... and so on
Since there are 15 girls and lower no of boys we need to find out which number of boys are there in 16, 36, 56.
16- 15 = 1
36 - 15 = 21
And 21 is more than 15 therefore the answer is 16 students. 15 girls and 1 boy.
Answer:
A,B,C,E
Step-by-step explanation: