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mojhsa [17]
3 years ago
7

Subtract -2x^2+4x-1 from 6x^2+3x-9

Mathematics
1 answer:
satela [25.4K]3 years ago
8 0
-8x^2+7x-10 should be the answer...if not go to connects it’s an app that helps and live people help you solve the problem
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Jeb is the local tennis pro at the country club, and he needs to know at what height the tennis ball needs to be when he hits it
suter [353]

Answer:

The height from ground, at which Jeb needs to hit the ball is 7.8 meters

Step-by-step explanation:

The given parameters are;

The distance away the tennis ball is hit = 20 meters;

The height of the tennis net = 0.3 m

The distance from the net the ball lands = 4 meters

The time the ball takes to land from the 0.3 m net height is given as follows;

t = √(h/(1/2×g)) = √(0.3/(1/2 × 9.8)) ≈ 0.2474

t ≈ 0.2474 seconds

The speed of the ball = Distance/Time = 4/0.2474 ≈ 16.166

The speed of the ball ≈ 16.166 m/s

The time it takes the ball to reach the net = 20/16.166 ≈ 1.24

The time it takes the ball to reach the net, tₓ ≈ 1.24 seconds

The height, hₓ the ball falls in 1.24 seconds is given as follows;

hₓ = 1/2·g·tₓ² = 1/2 × 9.8 × 1.24² = 7.5

The height, hₓ the ball falls in 1.24 seconds = 7.5 m

The height the ball falls in the time taken to reach the net from 20 meters = The height, hₓ the ball falls in 1.24 seconds

Therefore, the height at which Jeb needs to hit the ball = The height the ball falls in the time taken to reach the net from 20 meters + The height of the net = 7.5 m + 0.3 m = 7.8 m

The height at which Jeb needs to hit the ball = 7.8 m

4 0
3 years ago
Please help I'm horrible at fractions and I need to finish this...<br> Solve and simplify
Tpy6a [65]

Answer:

your answer would be 1/24

Step-by-step explanation:

this is because if you half it you get 5/120

then divide each by 5 to get 1/24

hope it helps!!

7 0
3 years ago
Read 2 more answers
The distance between itahari and Damak is
Ludmilka [50]

Answer:

8 km by motorbike.

Step-by-step explanation:

The distance between itahari and Damak is  42 km.

Mr. Dhamala travelled 18.325 km by a  bus / 15.675 km by a taxi and the remaining distance by a motorbike.

Let he covered x distance by motorbike. So,

Remaining distance = Total distance -(distance covered by bus + distance by taxi)

= 42 -(18.325 +15.675 )

= 42-34

= 8 km

So, he travelled 8 km by motorbike.

8 0
2 years ago
Which expression represents the product of 3 and y? 3 + y 3 − y 3 over y 3y
Eva8 [605]

Answer:

3y is the expression that represents the product of 3 and y

5 0
3 years ago
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
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