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motikmotik
3 years ago
7

um fazendeiro comprou a mesma quantidade de bezerros e vacas por 476.000. pagou 800 por um bezerro e 2000 por uma vaca,quantos a

nimais de cada espécie ele comprou?
Mathematics
1 answer:
marshall27 [118]3 years ago
6 0

Answer:

  • <u>The farmer bought 170 animals of each species</u>.

Step-by-step explanation:

The translation of the question into English is:

<em>"a farmer bought the same number of calves and cows for 476,000. He/she paid 800 for a calf and 2000 for a cow, how many animals of each species did he/she buy?"</em>

<em />

<h2>Solution to the problem</h2>

<u>1. Choose the variable's name and translate the verbal statements into algebraic expressions:</u>

  • a) number of calves or cows: x
  • b) He/she paid 800 for a calf: 800x
  • c) He/she paid 2,000 for a cow: 2000x
  • d) For 476,00: 800x + 2000x = 476,000 . . . .  this is your equation

<u />

<u>2. Solve the equation:</u>

<u>a) Write the equation:</u>

    800x+2,000x=476,000

<u>b) Add like terms:</u>

    2,800x=476,000

<u>c) Use division property of equalities: divide both sides by 800:</u>

    x=476,000/2,800=170

<u>d) Translate the solution into a verbal statement:</u>

Since x represents both the number of calves and the number of cows, the answer is:

  • <u>The farmer bought 170 animals of each species</u>.
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