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KonstantinChe [14]
3 years ago
7

Please help and answer

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

so the answer is B,D,E,F

and question a is B i guess

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15ab-9a^2-6  \frac{1}{4} b^2 \\  \\  = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\  \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\  \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\  \\   = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2  \\  \\ =  -  \{ - 15ab + (3a)^2 +  \bigg(\frac{5}{2} b \bigg)^2  \} \\  \\ =  -  \{ (3a)^2 +  \bigg(\frac{5}{2} b \bigg)^2 - 15ab  \} \\  \\  =   - \bigg(3a -  \frac{5}{2} b \bigg)^{2}

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