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aniked [119]
3 years ago
12

I do not understand how to do this?

Mathematics
2 answers:
djverab [1.8K]3 years ago
4 0

Answer:

try pressing the help button, it looks like it mightve glitched

Step-by-step explanation:

laila [671]3 years ago
3 0

Answer:

-8,-7

Step-by-step explanation:

I think

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Write 16^8 as a power with a base of 4
ruslelena [56]

(4^2)^8 would be the answer 4^2=16 and 16^8 is the same thing

4 0
3 years ago
Read 2 more answers
Bill deposits $3,000 into an account that pays simple interest at a rate of 3% per year. How much interest will he be paid in th
Sholpan [36]

Answer:

The interest he will be paid in the first 4 years is $360

Step-by-step explanation:

The rule of the simple interest is I = Prt, where

  • P is the initial deposit
  • r is the rate in decimal
  • t is the time

∵ Bill deposits $3,000 into an account

∴ P = 3000

∵ The account pays simple interest at a rate of 3% per year

∴ r = 3% = 3 ÷ 100 = 0.03

∵ The time is 4 years

∴ t = 4

→ Substitute these values in the rule above

∵ I = 3000(0.03)(4)

∴ I = 360 dollars

∴ The interest he will be paid in the first 4 years is $360

6 0
3 years ago
given the vector with a manitude of 9m at an angle a of -80 degrees, decompose this vector into two vector components oarallel t
lana [24]

Answer:

We have the magnitude, M, and the angle A.

(The angle is always measured from the +x-axis)

Then we have that:

x = M*cos(A)

y = M*sin(A)

in this case:

M = 9m

A = -80°

x = 9m*cos(-80°) = 1.562

y = 9m*sin(-80) = -8.86m

Now, the component parallel to the x axis is:

x = 9m*cos(-80°) = 1.562 m

And the slope of something parallel to the x-axis is always zero, as this is a constant line.

3 0
3 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
How do you multiply hundreds by tens?
coldgirl [10]

Answer:

to multiply any number by 10, just tag ONE zero on the end. To multiply any number by 100, just tag TWO zeros on the end. To multiply any number by 1,000, just tag THREE zeros on the end. Note especially what happens when the number you multiply already ends in a zero or zeros.

5 0
3 years ago
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