I do not understand how to do this?

Mathematics

2 answers:

djverab [1.8K]3 years ago

4 0

Answer:

try pressing the help button, it looks like it mightve glitched

Step-by-step explanation:

laila [671]3 years ago

3 0

Answer:

-8,-7

Step-by-step explanation:

I think

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Consider the 20 points of a 4×5 grid. You randomly choose two points from the 20 points. What is the probability that the two po

Serhud [2]

Answer:

The probability of both points falling in the same row or column is 7/19, or approximately 37%

Step-by-step explanation:

The easiest way to solve this is to think of it rephrased as "what is the probability that your second point will be in the same row or column as your first point". With that frame of reference, you can simply consider how many other points are left that do or do not fall in line with the selected one.

After selecting one, there are 19 points left.

The row that the first one falls in will have 3 remaining empty points.

The column will have 4 remaining empty points.

Add those up and you have 7 possible points that meet the conditions being checked.

So the probability of both points falling in the same row or column is 7/19, or approximately 37%

6 0

3 years ago

A recent survey determined the IQ score of a random selection of residents of Alaska. The accompanying relative frequency distri

ycow [4]

Answer:

The class width is 20

Step-by-step explanation:

In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.

We use the first two classes to calculate the class width by using their respective upper limits;

Class width = 89 - 69

Class width = 20

4 0

3 years ago

Find the length AB round your answer to the tenth

Kobotan [32]

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$AB = \sqrt{ ({3 - ( - 2)})^{2} + ({4 - 0})^{2} } \\$