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2 years ago

Please help solve this problem.

Mathematics

1 answer:

I am Lyosha [343]2 years ago

8 0

Answer:

Ang hirap naman niyan bakit kaya lahat na module mahirap

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Help meeee please eeee

Sphinxa [80]

Answer:

112 ft³

Step-by-step explanation:

→ Length (l) = 7 ft

→ Breadth (b) = 4 ft

→ Height (h) = 4 ft

Formula we use,

→ l × b × h

The volume of cuboid will be,

→ l × b × h

→ 7 × 4 × 4

→ [ 112 ft³ ]

Hence, the volume is 112 ft³.

8 0

1 year ago

Will mark 5 stars

lyudmila [28]

R is also known as the correlation coefficient. Hence your statement is ...
B. False

8 0

3 years ago

Which inequality is equivalent to this one?<br> Help with this question

Ira Lisetskai [31]

Answer:

A. the first one

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Pedro and Carmela are cleaning their kitchen. It takes Pedro 3 hours to clean the kitchen by himself, while Carmela can clean th

Igoryamba

Answer:

Step-by-step explanation:

Here, we want to choose the equation representing the time it will take if they worked together

Let the amount of tasks to be done be t

pedro will work at a rate of t/3

Camela will take t/2

So the joint rate will be

t/2 + t/3

This joint rate will be equal to 1

Thus, we have

t/2 + t/3 = 1

5 0

2 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

3 years ago