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Nezavi [6.7K]
3 years ago
12

Can anyone help me with this please! I don’t know what to do

Mathematics
1 answer:
NeX [460]3 years ago
3 0
50 out of 100 is half of the class; half of the circle will represent students going to college.  25 is a quarter of the class; a quarter of the circle will represent students not going to college.  25 is a quarter of the class; a quarter of the circle will represent students undecided about going to college.

The circle graph should look something like this:

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Can someone tell me this? I dont get it.
Harman [31]

Answer:

Step-by-step explanation:

Numbers 1 and 4 are perimeter questions so all you do is add up all the sides and the label is cm. For #2, this is an area problem and the area for a rectangle is length times width, so multiply the 2 together and the label is inches squared. For #3, the volume formula for a cube is side*side*side and the label for this is feet cubed. For #5, the area for a triangle is .5 times the base times the height, and the label is mm-squared. That should help you get all the answers on your wn. Very, very simple.

3 0
3 years ago
NEED ANSWERS ASAP
NARA [144]
The answer is 54 pi in^3. All you have to do is multiply 3x3, then multiply that by 6 and you get the answer 54.
5 0
3 years ago
Write a model for the statement V varies jointly as h and the fifth power of r. Group of answer choices LaTeX: V=khr^5 V = k h r
hjlf

Answer:

Option A)

V = khr^5

Step-by-step explanation:

We are given the following in the question:

V varies jointly as h and the fifth power of r.

V\propto h\\V\propto r^5

Combing the two equations, we get,

V\propto hr^5

Now, removing the sign of proportionality and adding the constant of proportionality, we get,

V = khr^5

where k is the constant of proportionality.

Thus, the correct answer is

Option A)

V = khr^5

7 0
3 years ago
A total of 326 adult and student tickets were sold for a high school play. The ticket prices were $8 for adults and $5 for stude
Trava [24]

Answer:

212 tickets were sold

Step-by-step explanation:

a (adult) + s (student) = 326

8a + 5s = 1972

-5(a + s = 326)

-5a-5s=1630

3a/3 = 342/3

a = 114

114 + s = 326

s = 212

4 0
3 years ago
Let A and B be two events in a sample space S such that
klasskru [66]
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)

</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
5 0
3 years ago
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