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tekilochka [14]
3 years ago
7

Darnell starts the month $952.43 in his checking account. Darnell buys an iPhone 7 for $217.49 with tax included, and two kindle

books that each cost $7.99. He pays with his checking account debit card. What is his new balance? The new iPhone 7 is not as awesome as promised, and Darnell returns it. What is his new balance? Explain how returning the phone is like the subtracting a negative number from his balance.
Mathematics
1 answer:
ki77a [65]3 years ago
8 0

Answer:

Therefore his new balance=$712.95

Therefore his new balance is  =$ 930.44  

Step-by-step explanation:

Darnell starts the month $ 952.43 in his checking account.

He buys an iPhone 7 for $ 217.49 with tax included and two kindle books that each $7.99.

The price of two books is =$(7.99× 2)= $ 15.98

Total amount that he paid for iPhone 7 and two books is =$(217.49+15.98)

                                                                                              =$233.47

Therefore his new balance = $(952.43- 233.47)

                                            =$712.95

The new iPhone 7 is not as awesome as promised , and Darnell returns it.

He will get the price of iPhone refund.

Therefore his new balance is $(712.95+217.49)

                                                =$ 930.44            

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You are making a necklace that is 9 inches long. You use 6 beads for each inch. What integer is the change in your supply of bea
nydimaria [60]
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3 years ago
A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if
topjm [15]

Answer:

a) The expected value is \frac{-1}{15}

b) The variance is  \frac{49}{45}

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is \binom{10}{2}.

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is \binom{5}{2}. Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is \binom{5}{1}\cdot \binom{5}{1}. So, we define the following probabilities.

Probability of winning: \frac{2\binom{5}{2}}{\binom{10}{2}}= \frac{4}{9}

Probability of losing \frac{(\binom{5}{1})^2}{\binom{10}{2}}\frac{5}{9}

Let X be the expected value of the amount you can win. Then,

E(X) = 1.10*probability of winning - 1 probability of losing =1.10\cdot  \frac{4}{9}-\frac{5}{9}=\frac{-1}{15}

Consider the expected value of the square of the amount you can win, Then

E(X^2) = (1.10^2)*probability of winning + probability of losing =1.10^2\cdot  \frac{4}{9}+\frac{5}{9}=\frac{82}{75}

We will use the following formula

Var(X) = E(X^2)-E(X)^2

Thus

Var(X) = \frac{82}{75}-(\frac{-1}{15})^2 = \frac{49}{45}

7 0
3 years ago
For the data in the table, write an equation for the direct variation.
melisa1 [442]

The equation of direct variation is,

\begin{gathered} y=kx \\ k=\frac{y}{x} \end{gathered}

Substitute the values of <em>y</em> and <em>x</em>.

\begin{gathered} k=\frac{5.4}{4} \\ k=1.35 \end{gathered}

So, the obtained equation will be <em>y</em>=1.35(x).

Let's check with the values of <em>x</em>.

1) If <em>x</em>=4

\begin{gathered} y=1.35x \\ y=1.35(4) \\ y=5.4 \end{gathered}

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4 0
11 months ago
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Helga [31]
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so out of 56 students who passed 42 females passed 42/56 = 3/4 = 0.75

out of 56 students who passed, 14 males passed which turns into 14/56 = 1/4 = 0.25

check work; 0.75 + 0.25 = 1.00

NOW WE ARE DOING FAILS.

15 + 5 = 20

so out of 20 students who failed, 15 females failed so it turns into 15/20 = 3/4 = 0.75

out of 20 students who failed, 5 males failed. 5/20 = 1/4 = 0.25

check work; 0.75 + 0.25 = 1.00

i hope this helped! :)

7 0
2 years ago
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