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Mandarinka [93]
3 years ago
9

From January to June, a company spent $60.00 per month on office supplies. In July, the price of office supplies increased by 15

% and remained the same for the rest of the year. How much did the company spend on office supplies for the year?
Mathematics
2 answers:
pochemuha3 years ago
5 0
The company would spend $69.00 a month on office supplies for the rest of the year.
Sunny_sXe [5.5K]3 years ago
5 0
For august -through- december the company spent $345
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6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP
adelina 88 [10]

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

     = 036^{o}

Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

       = 12.703

y = 12.70 km

\frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

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3 years ago
C is between B and D <br> BC = 8x +13<br> CD= 12x -73<br> BD =320 <br> find the value of x
pentagon [3]

Answer:

..

...

Step-by-step explanation:

..

7 0
3 years ago
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What is 4/5 of 20.5?
ira [324]
16.4
20.5/5=4.1
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Please answer! I give brainliest when I can! It make my day :-) ASAP :-(
hjlf

Answer:

A=1/2h(7+11) or A=1/2h(77)

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Step-by-step explanation:

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This answer is 12 
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