Answer:
Width = 2
Length = 5
Step-by-step explanation:
let A be the area of the rectangle
L be the length of the rectangle
w be the width of the rectangle
<u><em>Formula</em></u>: ‘<u><em>area of a rectangle</em></u>’
A = L × w
…………………………………………………
A = L × w
⇔ 10 = (w + 3) × w
⇔ 10 = w² + 3w
⇔ w² + 3w - 10 = 0
<u><em>Solving the quadratic equation</em></u> w² + 3w - 10 = 0 :
Δ = 3² - 4(1)(-10) = 9 - (-40) = 9 + 40 = 49
then √Δ = 7
-5 is not valid ,because w represents the width
which must be a positive number
Then w = 2
<u><em>Conclusion</em></u>:
Width = 2
Length = 2 + 3 = 5
Answer:
87
Step-by-step explanation:
f(x) = 2x+1
It will be 69 because 68 is wrong and 69 is right
Answer: In the resulting equation: " a² - 12a + 32 = 0 " ;
________________________________________________________
The "coefficient" of the "a" term is: " - 12" .
________________________________________________________
The "constant" is: " 32 " .
________________________________________________________
Explanation:
________________________________________________________
Let: "a = x² + 4 " .
Given: (x² + 4)² + 32 = 12x² + 48 ;
______________________________________________________
Factor: "12x² + 48" into " (x² + 4) " ;
"12x² + 48" = 12 (x² + 4) " ;
______________________________________________________
Given: (x² + 4)² + 32 = 12x² + 48 ;
rewrite as; "a² + 32 = 12a " ;
Subtract "12a" from each side of the equation;
"a² + 32 - 12a = 12a - 12a ;
to get:
" a² - 12a + 32 = 0 " .
___________________________________________________
The coefficient of the "a" term; that is:
The "coefficient" of " -12a" ; is: "- 12" .
The constant is: "32<span>" .
</span>___________________________________________________
Answer:
are this if its a function or not?
