what is the center of a circle whose equation is x2 + y2 – 12x – 2y + 12 = 0? o (-12,-2) o (-6, -1) o (6, 1) (12, 2)
1 answer:
Answer:
(6,1)
Step-by-step explanation:
1.) group the x and y terms (and move the constant to the other side)
x²-12x+y²-2y= -12
divide the coeficcents for the terms with just 1 or 1 x variable by 2 and then square it (and add that to both sides)
x²-12x+36+y²-2y+1= -12+36+1
factor
(x-6)²+(y-1)²= 25
the center is therefore (6,1)
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Answer:
2600 AND 1700
Step-by-step explanation:
both accounts rep by A and B
a + b = 4300
0.02a + 0.13b = 273
a = 4300 - b
0.02(4300 - b) + 0.13b = 273
86 - 0.02b + 0.13b = 273
-0.11b = -187
b = 1700
a = 4300 - 1700
a = 2600
Simplify 28/2 to 14
16 + 14 - 6/10 - 4x^2
Simplify 6/10 to 3/5
16 + 14 - 3/5 - 4x^2
Collect like terms
-4x^2 + (16 + 14 - 3/5)
Simplify
<u>-4x^2 + 147/5</u>
0
is the answer to the prob.
The first one in x _> 12
The second one is x<24
Good luck!
Answer:
This is GP with the first term of 512 and common ratio of 1/2
<u>The formula for nth term is:</u>
<u>The number of teams after the 4th round:</u>
- a₄ = 512*(1/2)⁴ = 32 teams
<u>Number of rounds to determine the champion:</u>
- 1 = 512*(1/2)ⁿ
- 2⁰ = 2⁹*2⁻ⁿ
- 0 = 9 - n
- n = 9 rounds
