Hi,
The total amount is 17.91608
How I got my answer:
100 + tip%/100 * 14.56 = amount with tips
100 + 15/100 * 14.56
115/100 * 14.56
1.15 * 14.56 = 16.744
100 + tax%/100 * amount with tips = total amount
100 + 7/100 * 16.744 = total amount
107/100 * 16.744
1.07 * 16.744
17.91608 = total amount
Hope this Helps you.
It looks like your equations are
7M - 2t = -30
5t - 12M = 115
<u>Solving by substitution</u>
Solve either equation for one variable. For example,
7M - 2t = -30 ⇒ t = (7M + 30)/2
Substitute this into the other equation and solve for M.
5 × (7M + 30)/2 - 12M = 115
5 (7M + 30) - 24M = 230
35M + 150 - 24M = 230
11M = 80
M = 80/11
Now solve for t.
t = (7 × (80/11) + 30)/2
t = (560/11 + 30)/2
t = (890/11)/2
t = 445/11
<u>Solving by elimination</u>
Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,
7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)
5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)
Now combining the equations eliminates the t terms, and
(-10t + 35M) + (10t - 24M) = -150 + 230
11M = 80
M = 80/11
It follows that
7 × (80/11) - 2t = -30
560/11 - 2t = -30
2t = 890/11
t = 445/11
Best Answer:<span> </span><span>So first we need both areas, then we can relate them, and then divide the circle by the square:
A(circle) = πr^2
A(square) = L*W or (2r)*(2r) which is (2r)^2
For the square, we know this is true because because the radius is half the diameter, so if we multiply the radius by 2, we get the length of one side of the square. We also know that the lengths of both sides of the square are the same by definition of a square.
Ratio: (πr^2)/(4r^2) = π/4</span>
Step-by-step explanation:
The rule is add 5 to x
6+5=11
n=11
Simplify:
37 - (-3)^2 + 30/(-3)x^2
= 37 + - 9 + - 10x^2
Combine like terms:
= 37 + - 9 + - 10x^2
= ( - 10x^2) + (37 + - 90
= - 10X^2 + 28
Answer: - 10x^2 + 28
To Factor:
37 - (- 3)^2 + 30/- 3x^2
- 10x^2 + 28
- 2(5x^2 - 14)
Answer: - 2(5x^2 - 14)
I simplify, and factor, because, you didn't really specify what you wanted help on with this equation. - Thanks -
Hope that helps!!!!
