Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
slope intercept form :
y=m+b
m=slope
If the line is parallel to y=2/3 x-0, the line will have the same slope, therefore the slope will be: 2/3.
Data:
(8,4)
m=2/3
y-y₀=m(x-x₀)
y-4=2/3(x-8)
y-4=2/3 x-16/3
y=2/3 x-16/3+4
y=2/3 x-4/3 (slope intercept form)
Answer: The equation of the line would be: y=2/3 x-4/3.
if we have the next slope "m",then the perendicular slope will be:
m´=-1/m
We have this equation: y=2/3 x+0; the slope is: m=2/3.
The perpendicular slope will be: m`=-1/(2/3)=-3/2
And the equation of the perpendicular line to : y=2/3 x+0, given the point (8,4) will be:
y-y₀=m(x-x₀)
y-4=-3/2 (x-8)
y-4=-3/2 x+12
y=-3/2x + 12+4
y=-3/2x+16
answer: the perpendicular line to y=2/3 x+0 , given the point (8,4) will be:
y=-3/2 x+16
Answer:
Any radical in the form can be written using a fractional exponent in the form . The relationship between and works for rational exponents that have a numerator of 1 as well. For example, the radical can also be written as , since any number remains the same value if it is raised to the first power.
Step-by-step explanation:
The four quadrants and the sign of coordinates is given as follows:
Quadrant I : (n, n ) both x and y positive.
Quadrant II : ( -n,n) = x negative and y positive.
Quadrant III : ( -n,-n) = both x and y negative.
Quadrant IV: (n, -n) = x positive and y negative.
So Based on the above concept , we can say that vertex C (-n,-n) has both x and y negative and so it lies in quadrant III.
Answer is Vertex C (-n,-n)
First simplify inside parenthasees
8-6x+12
-6x+8+12
-6x+20
distributive poproty
a(b+c)=ab+ac
1/4(-6x+20)=-6x/4+20/4=
-3/2x+5
Answer:
The Answer is C .............
