Factorise 2x^2

Miley and Cole ended up making the same number of biscuits for a bake sale at school, even though Miley made them in batches of

german

Answer: $77\ biscuits$

Step-by-step explanation:

For this exercise you need to find the Least Common Multiple (LCM).

The steps two find the Least Common Multiple are shown below:

1. Descompose the numbers into their prime factors.

2. Multiply the commons an non commons with the highest exponent. The product obtained will be the Least Common Multiple.

Knowing this, you can find the Least Common Multiple between 7 and 11. This is:

$7=7\\11=11\\\\LCM=7*11\\\\LCM=77$

Therefore the smallest number of biscuits each must have baked is: $77\ biscuits$

8 0

3 years ago

Please solve this problem... I will mark you brainliest

Blababa [14]

I hope this helps you

8 0

3 years ago

Problem 11-93 Waltner Corporation s management... Waltner Corporation's management reports that its average delivery cycle time

Marat540 [252]

Complete question is;

Waltner Corporation's management reports that its average delivery cycle time is 25 days, its average throughput time is 7.7 days, its manufacturing cycle efficiency (MCE) is 0.43, its average move time is 0.3 day, and its average queue time is 3.00 days. Required: a. What is the wait time?

b. What is the process time?

c. What is the inspection time?

Answer:

A) Wait time = 17.3 days

B) Process time = 3.311 days

C) Inspection time = 0.789 days

Step-by-step explanation:

A) we are given;

Delivery cycle time = 25 days

throughput time = 7.7 days

The formula for wait time is calculated from;

Delivery time = wait time + throughput time

So, wait time = Delivery time - throughput time

Wait time = 25 - 7.7 = 17.3 days

B) The process time is calculated from;

MCE = Process time/throughput time

So, process time = MCE x throughput time

We are given MCE = 0.43,thus, and we already know throughput time. Thus;

Process time = 0.43 x 7.7 = 3.311 days

C) The inspection time is gotten from;

throughput time = Process time + Inspection time + Move time + Queue time

Making inspection time the subject;

inspection time = throughput time - Process time - Move time - Queue time

Move time = 0.3 days

Queue time = 3 days.

Thus;

inspection time = 7.7 - 3.311 - 0.3 - 3.3 = 0.789 days

3 0

4 years ago

At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. T

OLEGan [10]

Answer:

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

$\text{Area of circle}=\pi r^2$ , where r represents radius of the circle.