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4 years ago

Solve the literal equation for m. y = mx + b

Mathematics

1 answer:

Luba_88 [7]4 years ago

3 0

Answer:

m = $\frac{y-b}{x}$

Step-by-step explanation:

given y = mx + b ( subtract b from both sides )

y - b = mx ( isolate m by dividing both sides by x )

$\frac{y-b}{x}$ = m

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The graph represents a function.

vladimir2022 [97]

(-5, 2) is the only point which we plot in given graph then it still represent a function.

<h3>What is Function?</h3>

A function is a special type of relation in which each and every element of set A have a unique image in its codomain set B.

Here, Given points on graph

{(-4, 2), (-2, -3), (2, 3), (3, -1)}

2 and -2 are already available in given ordered pair.

so only (-5, 2) is the only option which satisfies the definition of function.

Thus, (-5, 2) is the only point which we plot in given graph then it still represent a function.

Learn more about function from:

brainly.com/question/12431044

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2 years ago

Does the point (0, 10) lie on the line y = 2x + 10?

denis-greek [22]

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4 years ago

Read 2 more answers

QUALITY CONTROL1)Specifications for a part for a DVD player state that the part should weigh between 24.6 and 25.6 ounces. The p

Phantasy [73]

Answer:

Step-by-step explanation:

Given that,

μ = 25.1

σ = 0.26

a) since standard deviation is ideal measure of dispersion , a combination of control chart for mean x and standard deviation known as

$\bar x \\\text {and}\\\mu$

Chart is more appropriate than $\bar x$ and R - chart for controlling process average and variability

so we use

$\bar x \\\text {and}\\\mu$ charts

n = 11

we have use 2 σ confidence

so, control unit for $\bar x$ chart are

upper control limit = $\mu +2\times\frac{ \sigma}{\sqrt{n} }$

lower control limit = $\mu -2\times\frac{ \sigma}{\sqrt{n} }$

control limit = μ

μ = 25.1

upper control limit =

$25.1+2\times \frac{0.26}{\sqrt{11} } \\\\=25.2567$

lower control limit =

$25.1-2\times \frac{0.26}{\sqrt{11} } \\\\=24.9432$

Upper control limit and lower control limit are in between the specification limits , that is in between 24.9 and 25.6

so, process is in control

c) if we use 3 sigma limit with n = 11

then

upper control limit = $\mu +3\times\frac{ \sigma}{\sqrt{n} }$

$25.1+3\times\frac{0.26}{\sqrt{11} } \\\\=25.3351$

lower control limit = $\mu -2\times\frac{ \sigma}{\sqrt{n} }$

$25.1-3\times\frac{0.26}{\sqrt{11} } \\\\=24.8648$

control limit is 25.1

Then, process is in control since upper control limit and lower control limit lies between specification limit

So, process is in control

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3 years ago

How many minutes does it take the duck to fly 1 kilometer?

andreyandreev [35.5K]

Answer:

0.25 minutes

Step-by-step explanation:

It will take 1/12 the time for the duck to fly 1/12 the distance. Therefore, it will take 3 * 1/12 minutes which is 0.25 (1/4 in fraction form).

Hope this helps :)

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2 years ago

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alexandr1967 [171]

Greater than 6 it’s labeled as 1 through 6 a fair dice has a probability of 16

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2 years ago