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murzikaleks [220]
3 years ago
12

One card from a deck of cards Is selected, it's is replaced, and another card is chosen. What is the probability that the first

card is a red card and the second is a diamond
Mathematics
1 answer:
Elis [28]3 years ago
6 0

Answer:

1/ 8

Step-by-step explanation:

Given that:

Number of red cards in deck = 26

Number of diamonds in deck = 13

Number of cards in deck = 52

Recall :

Probability = required outcome / Total possible outcomes

Probability of choosing a red :

P(red) = 26 / 52 = 1/2

With replacement :

Probability of diamond :

P(diamond) = 13 / 52 = 1/4

Hence,

Probability of first card red, then second card diamond equals

P(red) * P(diamond)

1/2 * 1/4

= 1/8

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<span>What is 6 [4•(72-63)÷3]?

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3 years ago
guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

#SPJ4

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1 year ago
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vazorg [7]

Answer:

3/10

Step-by-step explanation:

There are 20 marbles.  6 of them are blue.

P = 6/20 = 3/10

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Answer:

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Range:{-2,5,6,23}

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By definition, a relation is a function if each input value has only one output value.

Given the relation:

(4,23)

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The domain is the set of the x-coordinates of each ordered pair (You do not need to write 4 twice):

Domain:{-6,3,4}

The range is the set of the y-coordinates of each ordered pair :

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Since the input value 4 has two different output values (23 and 6), the relation is not a function.

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