Answer:
begin{aligned}
& x = \frac{D_x}{D} = \frac{-616}{-154} = 4 \\
& y = \frac{D_y}{D} = \frac{ 616}{-154} = -4 \\
& z = \frac{D_z}{D} = \frac{-770}{-154} = 5
\end{aligned}
Step-by-step explanation:
We can use the substitution method to solve this problem.
The second equation is

, so we can plug in 2x for 'y' in the first equation:


Multiply:

Combine like terms:

This is the x-value of our solution, we can plug this into any of the two equations to find the y-value:


Multiply:

This is the y-value of our solution. So our entire solution is (3, 6).
Ok so the first thing you would do is input the number where The variables are in the equation so 8^2-5(4)/4
The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement. Yes, there is a "relationship" regarding the tangent of the two acute angles (A and B) in a right triangle.
First we need to find the slope of the function
The slope of a function is equal to

So now we plug this into the equation and find the slope (M will represent the slope)

So the slope is -3/2
Now we can use point-slope form.
Point slope form is represented by

So when we plug in our values we get

So the equation is
Y = -3/2X-7/2