I know two ways that we can use in this problem, it depends on your knowledge in your math class.
The first way is using the combinatorial formula, and probability:
P = possibles outcomes from the event/ all outcomes from the experiment
Using combinatoria P = (2C2*4C1)/(6C3)
2C2 is the possibles ways to get two defectives and we calculate that:
2C2=2!/(2!*(2-2)!)=1
Then, 4C1 is the possibles ways to get 1 no defective (remember you need only 3 test and you expect 2 are defective from the question), calculating:
4C1=4!/(1!*(4-1)!)=4
And 6C3 represents the all possible ways to get 3 calculators (no matter if they defective or not), calculating:
6C3=6!/(3!*(6-3)!)=20
Apply p formula:
<span>P = (1*4)/20 = 1/5 = 0.2</span> in percertage 20%
The another way to calculate this problem is using the tree diagram or multiplication rule:
P=(2/6)*(1/5)*(4/4)=1/15 (here you are saying the order of computer, first and second defective and the last one no defective)
P=(2/6)*(4/5)*(1/4)=1/15 ( the second is no defective, and the others are defective)
P=(4/6)*(2/5)*(1/4)=1/15 (the first one is no defective and the others are defective)
Finally add the three result above, and get the answer:
<span>P=1/15+1/15+1/15 = 3/15 = 1/5 = </span>0.2
The y is the same for both equations. Equate them
-x - 5 = 2x + 4 Add x to both sides
- 5 = 3x + 4 Subtract 4 from both sides.
- 9 = 3x Divide by 3
x = -9 / 3
x = - 3
y = - x - 5
y = -(-3) - 5
y = - 2
So that point is where the two equations meet.
To see the graph of your question on the internet, go to
Wolframalpha.com
and put this string in the question space.
y = -x - 5; y = 2x + 4 Note the semi colon in the middle.
To the moderator: This is my own work. I'm using Wolfram to get the answer.
Answer:
every 10th student entering the school
Step-by-step explanation:
An odd or far from average result on a graph or chart is called an outlier.
Well you could multiply 432 by 0.75, or you can divide it by 4 and then multiply it by 3. Either way your answer is 324.
