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3 years ago

Which statement about the graph of y= 3x+5 is correct?

Mathematics

1 answer:

Ymorist [56]3 years ago

6 0

Answer:

b. The line passes through the ordered pair (0,5) and has a slope of 3.

Step-by-step explanation:

The equation given is in slope-intercept form.

$y= mx+b$

m = slope

b = y-intercept

The slope is 3 in the equation. 3 is in m's spot.

$y=\boxed{m}x+b\\\\y=\boxed{3}x+b$

The y-intercept is 5. This means that the line will pass through (0,5).

$y=mx+\boxed{b}\\\\y=3x+\boxed{5}$

The correct option should be B.

Hope this helps.

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Find the projection of u onto v<br> URGENT HELP

padilas [110]

Given:

Two vectors are:

$u=\left$

$v=\left$

To find:

The projection of u onto v.

Solution:

Magnitude of a vector $v=\left$ is:

$|v|=\sqrt{a^2+b^2}$

Dot product of two vector $v_1=\left$ and $v_2=\left$ is:

$v_1\cdot v_2=a_1a_2+b_1b_2$

Formula for projection of u onto v is:

$Proj_vu=\dfrac{u\cdot v}{|v|^2}v$

$Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left$

$Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left$

$Proj_vu=\dfrac{0+102}{293}\left$

On further simplification, we get

$Proj_vu=\dfrac{102}{293}\left$

$Proj_vu=\left$

Therefore, the projection of u onto v is $Proj_vu=\left$ .

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3 years ago