Step-by-step explanation:
12x - 6 is your answer in simplified form
Answer:
4,000 bottles.
Step-by-step explanation:
Given that the patient needs a total dose of 50 grams of albumin, and the pharmacy has bottles of 50 milligrams with 25% albumin, to determine how many bottles the patient should purchase the following calculation must be performed:
1 g = 1000 mg
50 g = 50,000 mg
50 x 0.25 = 12.5
50,000 / 12.5 = X
4,000 = X
Therefore, the patient must purchase 4,000 bottles to obtain the required dosage.
The answer is √91 feet (which is the same as 9.54 feet).
Imagine this as a right triangle. A length of the foot is actually a hypotenuse (c). The distance from wall's base to the ladder foot is one of the sides of the triangle (let it be a).
So, using the Pythagorean theorem:
c² = a² + b²
It is given:
c = 10 feet
a = 3 feet
b = ?
c² = a² + b²
⇒ 10² = 3² + b²
100 = 9 + b²
b² = 100 - 9 = 91
⇒ b = √b² = √91 ≈ 9.54 feet
The way you find profit is to subtract the revenue and the cost
Profit = Revenue - Cost
The revenue is the amount of money coming in, the cost is the amount of money going out. The goal of course is to have the revenue larger than the cost so that the profit is positive.
So the equation given is
P = 7.5n - (2.25n+15)
and its in the form
P = R - C
where...
R = 7.5n is the revenue equation
C = 2.25n+15 is the cost equation
Focus on the revenue equation
R = 7.5n
which is the same as
R = 7.50*n
This tells us that Sandra pulls in a total of 7.50*n dollars where n is some positive whole number. It represents the number of necklaces sold. For example, if she sold n = 10 necklaces, then
R = 7.50*n
R = 7.50*10
R = 750
meaning that Sandra has made $750 in revenue
As you can see above, the revenue is computed by multiplying the price per necklace ($7.50) by the number of necklaces sold (n) to get R = 7.50*n
So that's why the answer is $7.50
Note: The 2.25 is part of the cost equation. This is known as the variable cost. It is the cost to make one necklace ignoring the fixed cost (eg: rent). The variable cost often doesn't stay the same, but algebra textbooks often simplify this aspect.
