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Alla [95]
2 years ago
14

HELP WITH GEO 50 POINTS explain it in simple terms pls

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

The missing angle is 45°, thus the right triangle is isosceles.

Then the 2 sides y and 7 are congruent.

Hence y = 7

Using Pythagoras' identity to calculate x

x² = 7² + 7² = 49 + 49 = 98

Take the square root of both sides

x = \sqrt{98} = \sqrt{49(2)} = 7\sqrt{2} ≈ 10

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Find the total surface area of this cuboid.<br> 5 cm<br> 2.3 cm<br> 7.5 cm
Mekhanik [1.2K]

Answer:

The total surface area of this cuboid is 132.5 sq.cm

8 0
2 years ago
An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours
Firdavs [7]

Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be  12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted  from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

n = \frac{50}{12.5}

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

d = 8 hours

Therefore the number of hours charged at the day rate  is 8 hours  and at the night rate is  4hours .

Hence proved



4 0
3 years ago
What is the mean for the set of data
AnnyKZ [126]

Answer:

B) 25

Step-by-step explanation:

First, you add up all the numbers. Then, you divide it by 9 which is the total amount of numbers there are.

7 0
3 years ago
The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir
Paha777 [63]

Answer:

95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                              P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean time = 5.15 years

            \sigma = sample standard deviation = 1.68 years

            n = sample of college graduates = 4400

            \mu = population mean time

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                               level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                              = [ 5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } } , 5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } } ]

                                             = [5.10 , 5.20]

Therefore, 95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
Read 2 more answers
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