18<x is the answer you are looking for. Glad to help.
Answer: $18
Explanation: 6x3
Answer:
254.34 ft^2
Step-by-step explanation:
A=1/4(3.14)d^2= 1/4(3.14)(8)^2= 254.34 ft^2
Answer: The correct option is (B) less than 2.
Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.
We are to find the possible value of X when the value of Y is 11.
Since Y varies directly with X, so we can write
![Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}](https://tex.z-dn.net/?f=Y%5Cpropto%20X%5C%5C%5C%5C%5CRightarrow%20Y%3Dkx~~~~~~~~~~~~~~~%28i%29%2C~~~~~~~~~%5Ctextup%7B%5Bwhere%20%27k%27%20is%20the%20constant%20of%20variation%5D%7D)
Since the rate of change is constant and is equal to 6, so we must have

So, from equation (i), we have

Now, when Y = 11, then from equation (ii), we get

Thus, the value of X is less than 2 when Y = 11.
Option (B) is CORRECT.
None of those are correct. x= 8 and 2/3