Please please help thanks

Packages of mixed-colored socks contain 8 pairs of socks. In each package, there are 5 pairs of White socks. How many pairs of w

BabaBlast [244]

125 5 diced by 40 = 125

6 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

3 years ago

The measure angle A is (2x+3), B (4x+2), C (2x-1). What are the measures of the angles?

Rudik [331]

Answer:

<A= 47, <B= 90, <C= 43

Step-by-step explanation:

2x +3 + 4x + 2 + 2x-1 = 180

8x + 4= 180

8x = 176

x =22

2x+3= 44+3= 47

4x+2 = 88+2 = 90

2x-1= 44-1 = 43

8 0

3 years ago

A college writing seminar increased its size by 50\PP, percent from the first to the second day. If the total number of students

Jobisdone [24]

Answer: There were 10 students in the class on the first day.

Step-by-step explanation:

Let x be the number of students of the first day.

Given: A college writing seminar increased its size by 50 percent from the first to the second day.

i.e. Number of students on second day = (Number of students on first day)+(50% of Number of students on first day)

= x +50% of x

= x+0.50x

= (1.50)x

=1.50x

Since, it is given that the total number of students in the seminar on the second day was 15.

i.e. $1.50x=15$

$\Rightarrow\ x=\dfrac{15}{1.5}\Rightarrow\ x=\dfrac{150}{15}\\\\\Rightarrow\ x=10$

Hence, there were 10 students in the class on the first day.

7 0

4 years ago

Answer each question below.

HACTEHA [7]

Answer:

$\huge\boxed{\sf L = 78\°}$

Step-by-step explanation:

<h3><u>Given that:</u></h3>

Exterior angle of L = 5x + 12

M = 3x - 2

N = 50

<h3><u>Statement:</u></h3>

Exterior angle is equal to the sum of non-adjacent interior angles.

So, the exterior angle that is adjacent to L is equal to the sum of non-adjacent sides (M and N) of the triangle.

Here,

Exterior angle of L = M + N

5x + 12 = 3x - 2 + 50

5x + 12 = 3x + 48

Subtract 12 to both sides

5x = 3x + 48 - 12

5x - 3x = 36

2x = 36

Divide 2 to both sides

x = 18

So,

<h3><u>Measure of angle M:</u></h3>

= 3x - 2

= 3 (18) - 2

= 54 - 2

= 52°

Now,

<h3><u>Measure of angle L:</u></h3>

Sum of all the interior angles of triangle is 180 degrees.

L + M + N = 180°

L + 52 + 50 = 180

L + 102 = 180

Subtract 102 to both sides

L = 180 - 102

L = 78°

$\rule[225]{225}{2}$

7 0

2 years ago