26 goes into 50 once. so put a 1 on top of the 5. multiply the 1 by 26, which is 26. write 26 underneath the "50" in 503. 50-26 = 24. bring down the 3 so you now have 243. how many times can 26 go into 243 evenly? the answer is 9. so put a 9 on top of the 0. multiply the 9 by 26 and you get 234. so whatever 243 - 234 equals, thats your decimal
The answer to both the subparts using the circumference of the circle is:
- (A) If an athlete runs around the track then the athlete traveled (168.78+73π)m.
- (B) The area of green space on the track is 0.64m².
<h3>What is a length of a rectangle?</h3>
- The length of the rectangle is traditionally thought of as being the longer of these two dimensions, however, when the rectangle is depicted standing on the ground, the vertical side is typically referred to as the length.
What is a circumference of a circle?
- The distance along a circle's perimeter is referred to as its circumference.
- Circumference of the circle formula: C = 2πr.
Here,
(A) A circuit of a racetrack is equal to the sum of the two lengths of a rectangle and the circumference of the circle.
We get:
- = 84.39 * 2 + 73π
- = (168.78 + 73π)m
(B) Let the area of the green space of the track is x.
Then, calculate as follows:
- 168.78 + xπ = 400
- x = (400 - 168.78)/π
- x = 73.64m
So, the inner circle of distance is 73.64 - 73 = 0.64m.
Therefore, the answer to both the subparts using the circumference of the circle is:
- (A) If an athlete runs around the track then the athlete traveled (168.78+73π)m.
- (B) The area of green space on the track is 0.64m².
To learn more about the circumference from the given link
brainly.com/question/18571680
#SPJ13
<h3>
Answer: A. 18*sqrt(3)</h3>
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Explanation:
We'll need the tangent rule
tan(angle) = opposite/adjacent
tan(R) = TH/HR
tan(30) = TH/54
sqrt(3)/3 = TH/54 ... use the unit circle
54*sqrt(3)/3 = TH .... multiply both sides by 54
(54/3)*sqrt(3) = TH
18*sqrt(3) = TH
TH = 18*sqrt(3) which points to <u>choice A</u> as the final answer
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An alternative method:
Triangle THR is a 30-60-90 triangle.
Let x be the measure of side TH. This side is opposite the smallest angle R = 30, so we consider this the short leg.
The hypotenuse is twice as long as x, so TR = 2x. This only applies to 30-60-90 triangles.
Now use the pythagorean theorem
a^2 + b^2 = c^2
(TH)^2 + (HR)^2 = (TR)^2
(x)^2 + (54)^2 = (2x)^2
x^2 + 2916 = 4x^2
2916 = 4x^2 - x^2
3x^2 = 2916
x^2 = 2916/3
x^2 = 972
x = sqrt(972)
x = sqrt(324*3)
x = sqrt(324)*sqrt(3)
x = 18*sqrt(3) which is the length of TH.
A slightly similar idea is to use the fact that if y is the long leg and x is the short leg, then y = x*sqrt(3). Plug in y = 54 and isolate x and you should get x = 18*sqrt(3). Again, this trick only works for 30-60-90 triangles.
Here is something you can do on your own, if you have a pencil and
a scrap of paper:
-- Draw a triangle. It has 3 sides. Count its angles.
-- Draw something with 4 sides. Count its angles.
-- Draw something with 5 sides. Count its angles.
-- Draw anything with 6 sides. Count its angles.
This doesn't PROVE anything, because you haven't tried polygons with
every possible number of sides, so there may be an exception to the rule.
But by trying only these few cases, you'll probably begin to notice a rule.
If you can't find a pencil and a scrap of paper, you can probably perform
this same experiment using a brain.