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astra-53 [7]
3 years ago
14

26 POINTS PLEASE HELP TY !!

Mathematics
2 answers:
Reil [10]3 years ago
4 0
200+12x=644 there’s your answer!
ira [324]3 years ago
3 0

Answer:

200+12x=644

Step-by-step explanation:

37 mark me brainlist

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weqwewe [10]
I believe it’s 80^, sorry if i’m wrong :)
8 0
3 years ago
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What is 5.06 times 2.10. Pease show work
Alecsey [184]

your \: answer \: is \: 10.626

im \: sorry \: i \: cant \: show \: work \: i \: used \: a \:   calculator

3 0
3 years ago
In how many ways can 5 people be selected from 11 to play on a basketball team
inessss [21]

This is the number of combinations of 5 from 11.

11C5 = 11! / 5!6!

a quick way to work it out is (11*10*9*8*7) / (5*4*3*2*1)

= 462 answer

6 0
3 years ago
Which of the following are solutions to the inequality below? Select all that apply.-96-51
sergij07 [2.7K]

You have the following inequality:

-51

In order to determine which are valid solutions of the previous inequality, take into account that any positive value for V is solution of the previous equation, because if V is positive, 96/V is also positive.

Then, the following area solutions:

V = 3

V = 6

V = 8

V = 4

6 0
1 year ago
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
4 years ago
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