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posledela
3 years ago
14

What is the mid-point of the two co-ordinates (-2,5) and (4,9)

Mathematics
2 answers:
yarga [219]3 years ago
6 0

Answer:

1,7.5

Step-by-step explanation:

Tasya [4]3 years ago
5 0

Answer:

1,7

Step-by-step explanation:

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Brian invests £4000 into his bank account.
GuDViN [60]

Answer:

10.24 years

Step-by-step explanation:

The computation of the time period is as follows:

As we know that

Amount = Principal × (1 + rate of interest)^time period

£8000 = £4000 × (1 + 0.07)^time period

£8,000 ÷ £4,000 = 1.07^time period

2 = 1.07^time period

Now apply the log to the both sides

log 2 ÷ log 1.07 = time period

= 10.24 years

7 0
3 years ago
The hardcover version of a book weighs twice as much as its paperback version. The hardcover book and the paperback together wei
jasenka [17]

I think  H=P*2/4.2 could work corrext me if im wrong please


5 0
3 years ago
Read 2 more answers
What is the gcf of 27 and 36
mestny [16]

The answer would be 9. 9x3=27 and 9x4=36. Although 3 fits into both, 9 is the BIGGER number that also fits into both of the numbers shown in the problem.

5 0
3 years ago
Read 2 more answers
10.4.1 .WP The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at ran
Sunny_sXe [5.5K]

Answer:

[-0.65;2.54]km

Step-by-step explanation:

Hello!

So, you need to find a 99%CI for the difference in mean life of two brands of radial tires. Since he assigned one tire of each brand at random to the two rear wheels of each car, in other words, every car tested had one rear tire of each brand at the same time, this test can be considered to be of paired samples.

           Brand 1    Brand 2    X₁-X₂

car 1:    36,925 ;   34,318   ; 2.607

car 2:   45,300 ;   42,280  ; 3.020

car 3:   36,240 ;    35,500 ; 0.740

car 4:   32,100  ;    31,950  ; 0.150

car 5:   37,210  ;    38,015  ; -.0805

car 6:   48,360 ;    47,800 ; 1.160

car 7:   38,200 ;    37,810  ; 0.390

car 8:   33,500 ;    33,215  ; 0.285

n= 8

With this in mind, we define the study variable as Xd= X₁-X₂

Where X₁ corresponds to the lifespan, in km, of a tire from Brand 1

and X₂ corresponds to the lifespan, in km, of a tire from Brand 2

so Xd will be the difference between the lifespan of the tires from Brand 1 and Brand 2.

This variable Xd~N(μd;δd²) (p-value for normality test is 0.4640)

To calculate the CI the best statistic is the Student's t with the following formula:

t= (xd[bar] - μd)/(Sd/√n) ~t₍ₙ₋₁₎

sample mean: xd[bar]= 0.94

standard deviation: Sd= 1.29

t_{8;0.995} = 3.355

xd[bar] ± t_{8;0.995}*(Sd/√n)

⇒ 0.94 ± 3.355*(1.29/√8)

[-0.65;2.54]km

The Confidence Interval can be compared to a pair of bilateral hypothesis. If we were to determine the following hypothesis

H₀:μd=0

H₁:μd≠0

Using the level of significance of 0.01 (complementary to the confidence level)

As the calculated confidence interval contains zero, we do not reject the null hypothesis, that is, there is no significant difference between the two tire brands.

I hope you have a SUPER day!

5 0
3 years ago
What is the solution set of the equation 30/x^2-9 +1=5/x-3
gizmo_the_mogwai [7]
\frac{30}{x^{2} - 9 + 1} = \frac{5}{x - 3} \\\frac{30}{x^{2} - 8} = \frac{5}{x - 3} \\5(x^{2} - 8) = 30(x - 3) \\5(x^{2}) - 5(8) = 30(x) - 30(3) \\5x^{2} - 40 = 30x - 90 \\5x^{2} + 50 = 30x \\5x^{2} - 30x + 50 = 0 \\5(x^{2}) - 5(6x) + 5(10) = 0 \\5(x^{2} - 6x + 10) = 0 \\\frac{5(x^{2} - 6x + 10)}{5} = \frac{0}{5} \\x^{2} - 6x + 10 = 0 \\x = \frac{-(-6) \± \sqrt{(-6)^{2} - 4(1)(10)}}{2(1)} \\x = \frac{6 \± \sqrt{36 - 40}}{2} \\x = \frac{6 \± \sqrt{-4}}{2} \\x = \frac{6 \± 2i}{2} \\x = 3 \± i \\x = 3 + i\ or\ x = 3 - i

The answer is D.
8 0
3 years ago
Read 2 more answers
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