The oldest “computer” is2,000 years old.
Very Easy Rodent-Oriented Netwide Index to Computerized Archives
Answer:
The statement is as follows:
print("{0:,.1f}".format(number))
Explanation:
Required
Statement to print 1234567.456 as 1,234,567.5
To do this, we make use of the format keyword, and we set the print format in the process.
To round up number to 1 decimal place, we use the following format:
"{0:,.1f}"
To include comma in the thousand place, we simply include a comma sign before the number of decimal place of the output; i.e. before 1
"{0:,.1f}"
So, the print statement is:
print("{0:,.1f}".format(number))
Answer:
- Step1: Check If the number is Positive or Negative.
- Step2: If it is positive then save the sign of it as 0.
- Step3: If it is negative then save the sign of it as 1.
- Step4: Covert the negative number to Positive.
- Step5: Convert the IEEE 754 to Binary.
- Step6: convert the integer part into binary form
- Step7: Convert fractional part into binary form
- Step8: To convert Integer part, Devide the number by 2 and note down the reminder and Keep deviding unless dividend is less than 2
- Step9: copy all the reminders together
- Step10: Multiply decimal part by 2 unless fractional part is 0.
- Step11: By noting down integral part, keep multiplying decimal part by new value of 2 untill perfect number is reached.
- Step6: Find the Mantissa.
- Step7: Concatinate the Sign, exponent and the mantissa.
Explanation:
For Example : 20.75
First step (converting 50 (in base 10) to binary):
- No is Positive
- By dividing 20 by 2, which gives 10 with no remainder 0.
- Now Devide 10 by 2, which gives 5 with a remainder of 0.
- Now Devide 5 by 2, which gives 2 the reminder as 1
- Now Devide 2 by 2, which gives 1 with reminder as 0
- Now devide 1 by 2, which gives 0 with reminder as 1
- We read the result from bottom to top which is 10100
Second part is to convert 0.75 to binary:
- We have to multiply 0.75 by 2, which gives 1.5. We keep only the integer part, which is 1.
- Now, we do 1.5 - 1, which gives 0.5. Now, We multiply 0.5 by 2, which gives 1.
- Now we do 1 - 1, which gives 0.
- Reading from Top to bottom will give 110
Final Answer is : 10100.110
Answer:
TRUE, The PC is always incremented by the same amount in fixed-length instruction set architectures.
Explanation:
Its TRUE that Program Counter ( PC ) is always incremented by the same amount in fixed - length instruction set architectures ( fixed length ISA) . As the instruction set length is fixed in fixed - length instruction set architectures, the Program Counter to fetch the next instruction set it has to be incremented by fixed length. This fixed length depends on the hardware of the architecture (the number of bytes each machine word contains and number of machine words per memory location)
