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snow_tiger [21]
3 years ago
8

Why is body language an important factor in a business meeting

Computers and Technology
1 answer:
slava [35]3 years ago
5 0

The importance of the body language in business. Body language is a language without spoken words, it is called non verbal communication. We use it all the time in our social life and business life so it is all about gestures movements and expressions made by people to deliver a specific message to other people. Business meetings are all about making a good impression.

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What is another name for repetition in programming?
BigorU [14]
The answer is Iteration
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In pre-shared key mode, a passphrase should be at least ________ characters long.
alexandr402 [8]
10.......................................

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Clara works behind a computer all day. She gets a lot of headaches, and her eyes have been hurting her lately. Her doctor diagno
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2 years ago
5.23 LAB: Contains the character
torisob [31]

Answer:

In C++:

#include<iostream>

#include<vector>

using namespace std;

int main() {

int len;

cout<<"Length: ";  cin>>len;

string inpt;

vector<string> vect;

for(int i =0;i<len;i++){

  cin>>inpt;

  vect.push_back(inpt); }

char ch;

cout<<"Input char: ";  cin>>ch;  

for(int i =0;i<len;i++){

  size_t found = vect.at(i).find(ch);  

      if (found != string::npos){

          cout<<vect.at(i)<<" ";

          i++;

      }

}  

return 0;

}

Explanation:

This declares the length of vector as integer

int len;

This prompts the user for length

cout<<"Length: ";  cin>>len;

This declares input as string

string inpt;

This declares string vector

vector<string> vect;

The following iteration gets input into the vector

for(int i =0;i<len;i++){

  cin>>inpt;

  vect.push_back(inpt); }

This declares ch as character

char ch;

This prompts the user for character

cout<<"Input char: ";  cin>>ch;  

The following iterates through the vector

for(int i =0;i<len;i++){

This checks if vector element contains the character

  size_t found = vect.at(i).find(ch);  

If found:

      if (found != string::npos){

Print out the vector element

          cout<<vect.at(i)<<" ";

And move to the next vector element

          i++;

      }

}  

7 0
2 years ago
How efficient would a 6-bit code be in asynchronous transmission if it had 1 parity bit, 1 start bit, and 2 stop bits?
Lana71 [14]
How efficient well if we are transmitting 6bits and we need 10 to transmit the 6 bits that would be 6/10 = .6 = 60% efficient.
7 0
3 years ago
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