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rjkz [21]
3 years ago
13

How do you calculate the potential energy by it's height and weight? and is there any other way to solve it?​

Physics
1 answer:
White raven [17]3 years ago
5 0

Answer:

PE = mgh

Explanation:

m is mass, g is gravitational constant (9.81) and h is height

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Answer to this????????
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3 years ago
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Whats the value of 1,152 Btu in joules?(a)1,964,445J(b)1,215,360J(c)2,485,664J(d)997,875J
Anvisha [2.4K]
In order to make any headway with this one, it might help
to know how many joules there are in one BTU, ya reckon ?

I went and looked it up on line, you're welcome.

       1 BTU  =  1055.06 joules .

So if you happen to have 1,152 BTU of energy,
there are 1055.06 joules in each one of them,
and the total is

                        (1,152 BTU) x (1,055.06 joule/BTU)

                   =          1,215,429.12 joules .

Scanning the choices for anything close, we notice that choice-'b'
is only about 0.006% less than my answer.  So that must be the one
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8 0
3 years ago
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A rocket is moving away from the solar system at a speed of 7.5 ✕ 103 m/s. It fires its engine, which ejects exhaust with a spee
Elodia [21]

Answer:

a.2.5x 10^3 m/s

b.mr=48kg/s

Explanation:

A rocket is moving away from the solar system at a speed of 7.5 ✕ 103 m/s. It fires its engine, which ejects exhaust with a speed of 5.0 ✕ 103 m/s relative to the rocket. The mass of the rocket at this time is 6.0 ✕ 104 kg, and its acceleration is 4.0 m/s2. What is the velocity of the exhaust relative to the solar system? (B) At what rate was the exhaust ejected during the firing?

velocity of the exhaust relative to the solar system

velocity of the rocket -velocity of the exhaust relative to the rocket.

7.5 ✕ 103 m/s-5.0 ✕ 103 m/s

2.5x 10^3 m/s

. b  we will look for the thrust of the rocket

T=ma

T=6.0 ✕ 104 kg*4.0 m/s2

T=2.4*10^5N

f=mass rate *velocity of the exhaust

T=2.4*10^5N=mr*5.0 ✕ 10^3 m/s

mr=2.4*10^5N/5.0 ✕ 10^3

mr=48kg/s

5 0
3 years ago
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