The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
x=-3, x=1, x=3.5, and x=5
Step-by-step explanation:
Given the critical points (turning points) which represent the maximum or the minimum points, the set of points that can be tested to solve the inequality will consist of points to the right and to the left of these points. The set of points that solve the inequality will be simply the points where the graph of the function crosses the x-axis. From these information, the set of points will be as given above
Answer:
The bottom is 11
The median is 12
Step-by-step explanation:
The median is the average of the top and bottom
(13+ 2x-3) /2 = 4x-16
Combine like terms
(10+2x)/2 = 4x-16
Divide by 2
5+x = 4x-16
Subtract x from each side
5+x-x = 4x-16-x
5 = 3x-16
Add 16 to each side
5+16 = 3x-16+16
21 = 3x
Divide by 3
21/3 = 3x/3
7 =x
The bottom is 2x-3 = 2*7-3 = 14-3 = 11
The median is 4x-16 = 4*7-16 = 28 -16 = 12
20 minutes = 1/3 of an hour
1/3 = 0.333
1/3 x 45mph = 15, so she drove 15 miles at 45mph
18-15 = 3
3 miles/ 20 mph = 0.15 hours
0.333+0.15 = 0.483 hours total
0.483 x 60 = 28.98 so approximately 29 minutes total driving time
7:15 + 29 minutes is 7:44 am she arrived at work
There is 36 ways the dice come up, 6 for each dice. thats 8/36 or 2/9. :)
