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VashaNatasha [74]
3 years ago
13

Help please im stuck

Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

-2x + 6y = 3

4x + 3y = 9

Answer: 2

Explanation:

-2(2)x + 6y = 3

4x + 3y = 9

-8x + 10y = 16

-4x - 5y = 13

Answer:  -1/2

Explanation:

-8(-1/2)x + 10y = 16

-4x - 5y = 13

3x - 8y = 1

6x + 5y = 12

Answer: -2

Explanation:

3(-2)x - 8y = 1

6x + 5y = 12

10x - 4y = -8

-5x + 6y + = 10

Answer: 1/2

Explanation:

10(1/2)x - 4y = -8

-5x + 6y + = 10

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LenKa [72]

Answer:

C

Step-by-step explanation:

The vertical line test is a test that you do by dragging a vertical straight line (pencil) across the graph diagonally

If the graph touches the line in more than 1 place at a time, it is not a function

6 0
4 years ago
What is the square root of 450​
RUDIKE [14]

Answer:

15\sqrt{2}      or       21.2132

Step-by-step explanation:

\sqrt{450}

\sqrt{15^{2} }   <em> </em>(root of a product is equal to the product of the roots of each factor)

\sqrt{15^{2} } \sqrt{2}                (simplify)

15\sqrt{2}    or   ≈ 21.2132

4 0
4 years ago
Read 2 more answers
Luis is building a doghouse.It is in the shape of a rectangular solid.It measures 4 feet high, 4 feet wide, and 5 feet deep.What
dmitriy555 [2]
Volume of the dog house is 80 ft.³
7 0
4 years ago
Read 2 more answers
The frequency, f, in Hz, at which a simple pendulum rocks back and forth is given by 1 , 2 g f π l = where g is the strength of
Monica [59]

Answer:

a. 0.9 Hz b. 0.37 Hz

Step-by-step explanation:

The frequency of the simple pendulum f = (1/2π)√g/l where g = acceleration due to gravity and l = length of pendulum

a. Find the frequency of a pendulum whose length is 1 foot and where the gravitational field is approximately 32 ft/s2

To find f on Earth, g = 32 ft/s² and l = 1 ft

So, f =  (1/2π)√(g/l)

f = (1/2π)√(32 ft/s²/1 ft)

f = (1/2π)√(32/s²)

f = (1/2π)(5.66 Hz)

f = 0.9 Hz

b. The strength of the gravitational field on the moon is about 1/6 as strong as on Earth.. Find the frequency of the same pendulum on the moon.

On the moon when acceleration due to gravity g' = g/6,

f =  (1/2π)√(g'/l)

f =  (1/2π)√(g/6l)

f = (1/2π)√[32 ft/s²/(6 × 1 ft)]

f = (1/2π)√(32/s²)/√6

f = (1/2π)(5.66 Hz)/√6

f = 0.9/√6 Hz

f = 0.37 Hz

3 0
3 years ago
Estimate then answer the equation.
Inessa [10]

Answer:

7\frac{1}{4} -2\frac{5}{12} =\frac{58}{12} =4\frac{10}{12}

Step-by-step explanation:

Given:

7\frac{1}{4} =\frac{7\times 4 +1}{4}=\frac{29}{4}

2\frac{5}{12}=\frac{12\times 2+5}{12}=\frac{29}{12}

To Find:

7\frac{1}{4} -2\frac{5}{12} =?

Solution

Substituting the above values we get

7\frac{1}{4} -2\frac{5}{12} =\frac{29}{4} -\frac{29}{12}

Now make both the denominator same by multiplying and dividing by 3 to the first term so we get

7\frac{1}{4} -2\frac{5}{12} =\frac{29\times 3}{4\times 3} -\frac{29}{12}\\\\7\frac{1}{4} -2\frac{5}{12} =\frac{87}{12} -\frac{29}{12}\\\\7\frac{1}{4} -2\frac{5}{12} =\frac{87-29}{12}\\\\7\frac{1}{4} -2\frac{5}{12} =\frac{58}{12} =4\frac{10}{12}

∴ 7\frac{1}{4} -2\frac{5}{12} =\frac{58}{12} =4\frac{10}{12}

6 0
4 years ago
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