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alina1380 [7]
3 years ago
12

Two small metal cubes with masses 2.0 g and 4.0 g are tied together by a 4.7-cm-long massless string and are at rest on a fricti

onless surface. Each is charged to +2.5 μC .
What is the energy of this system?
Express your answer using two significant figures.
What is the tension in the string?
Express your answer using two significant figures.
The string is cut. What is the speed of each sphere when they are far apart?
Hint: There are two conserved quantities. Make use of both.
Express your answers using two significant figures. Enter your answers numerically separated by a comma.
(v2g,v4g)=_____m/s
Physics
1 answer:
Scilla [17]3 years ago
7 0

Answer:

1.2J

26 N

(-28, 14) m/s

Explanation:

energy

U = kQq / d = 8.99*10^9 * (2.5*10^-6C)² / 0.047m

U = 0.0562/0.047

U = 1.20 J

to two significant figures

tension

T = kQq / d²

T = U / d

T = 1.2 / 0.047

T = 25.53 N = 26 N to 2 sf

Momentum is conserved, and the initial momentum is zero:

0 = 0.0020 * V2 + 0.0040 * V4

so

V2 = -2 * V4

Energy is also conserved:

½ * 0.0020 * (-2V4)² + ½ * 0.0040 * (V4)² = 1.2 J

-½ * 0.0080 * V4² + ½ * 0.0040 * V4² = 1.2 J

-0.0040V4² + 0.002V4² = 1.2 J

0.0060V4² = 1.2 J

V4² = 1.2/0.0060

V4² = 200

V4 = √200

V4 = 14 m/s

and since V2 = -2 * V4

V2 = -28 m/s

(V2, V4) = (-28, 14)

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