Answer:
1960.32306 kg/s
Explanation:
m = Mass of water = 1 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height from which the water will fall
Potential Energy
One megawatts of power is required
So, flow rate
1960.32306 kg/s is required to produce a megawatt of power
Answer:
drag and drop each feature into the correct category
If the ladder is vertical, then the work done in ascending equals his increase in potential energy.
For a man of mass (m) climbing height (h), the PE is (mgh), where g is the acceleration due to gravity.
If he does this in time t, his average power (rate of working) is:
mgh / t
= 80 * 9.81 * 6 / 12
= 392.4 W.
If the ladder is not vertical but inclined at an angle the horizontal, the power is mgh sin(a) / t.
The answer is 48Kmh because it is 120km divided by 2.5 or 2 and a half hours
Answer:
3 m/s
Explanation:
The momentum of an obejct is given by
where
m is the mass of the object
v is the velocity of the object
For the ball in this problem, we know:
is the momentum
is the mass
Therefore, we can re-arrange the equation to find v, the velocity of the ball:
