Answer:
KE = KE (incidental) - KE of emitted photons
or KE = h * f - Wf
So h * f = KE + Wf = 1.2 + 1.88 = 3.08 incident energy
If you double the frequency then h * f = 6.16
KE = 6.16 - 1.2 = 4.96 eV
Yes ggejekkekwujhhnjhhdndnksiiieinrnnfjdjjnnsnndnbduiiitnnfnsoqoosofndbdod
Answer:
Explanation:
dU= dq+w
dU is change in internal energy of the system
dq is the amount heat added or released by the system which be positive or negative respectivelý
And w is the amount of work done by the system or on the system which will be positive or negative respectively.
Hence,
dU= 250+80= 330 J
The change will be positive
