3 years ago

When light reflects off a rough surface, what happens to the image?

Physics

1 answer:

user100 [1]3 years ago

6 0

Answer:

<h3>D. NO MAGE IS FORMED</h3>

Explanation:

<h2>#CARRY ON LEARNING#MARK BRAINLITS</h2>

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1) Think of planting a tree. You dig the hole, put it in, and fill it back in. Next,

pogonyaev

Answer:

at the top of the tree I hope it will help you please follow me

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2 years ago

An object is traveling with a constant velocity of 5 m/s. How far will it have gone after 7 s?

kozerog [31]

<h3>Answer:</h3>

35 meters

<h3>Explanation:</h3>

<u>Data given;</u>

Velocity of an object = 5 m/s
Time taken = 7 s

We are required to calculate how far the object traveled.

We need to know that;

Velocity = Displacement ÷ time

Therefore;

Displacement = Velocity × time

= 5 m/s × 7 s

= 35 m

Therefore; the object traveled 35 meters

6 0

3 years ago

Make the following conversion.

anastassius [24]

The answer is 0.00230 cm

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3 years ago

Read 2 more answers

A sled of mass 80 kg starts from rest and slides down an 18° incline 90 m long. It then travels for 20 m horizontally before sta

yaroslaw [1]

Answer:

net work done by friction = - 2205 J

Explanation:

given,

mass of sled = 80 kg

slide down at an angle of 18°

length = 90 m

travel horizontally = 20 m before starting back up a 16° incline.

net work = ?

$h_i = initial\ height$

$h_i = L_i Sin 18^0$

$h_i = 90 sin 18^0$

$h_i = 27.81\ m$

$h_f = Final\ height$

$h_f = L_f Sin 16^0$

$h_f = 90 sin 16^0$

$h_f =24.81\ m$

net work done by friction = change in potential energy

= mg (h_f - h_i)

= (75) (9.8) (- 27.81 + 24.81)

net work done by friction = - 2205 J

7 0

3 years ago

Calculate the KE of a 3.1 kg toy cart that moves at 4.8 m/s. Calculate the KE of the same cart at twice the speed.

lisov135 [29]

When v= 4.8 m/s:

E.K=mv²/2
=3,1(4.8)²/2
=35.712J

when v= 2(4.8):

E.K=mv²/2
=3.1(9.6)²/2
=142.848J

4 0

3 years ago