Answer:
The total distance traveled is 736 m
Solution:
According to the question:
Initial velocity, v = 0
(since, the car is starting from rest)
Time taken, t = 8 s
Now, the distance covered by it in 8 s is given by the second eqn of motion:
Now, to calculate the velocity, we use eqn 1 of motion:
v' = v + at
v' = 0 + 4(8) = 32 m/s
Now, the distance traveled by the car with uniform velocity of 32 m/s for t' = 19 s:
distance, d' = v't'
Total distance traveled = d + d' = 128 + 608 = 736 m
Answer:
0.02 Ns
Explanation:
From the question given above, the following data were obtained:
Force (F) = 5 N
Time (t) = 4 ms
Change in momentum =?
Next, we shall convert 4 ms to s. This can be obtained as follow:
1 ms = 1×10¯³ s
Therefore,
4 ms = 4 ms × 1×10¯³ s / 1 ms
4 ms = 4×10¯³ s
Thus, 4 ms is equivalent to 4×10¯³ s
Change in momentum = Impulse
Impulse (I) = Force (F) × time (t)
Change in momentum = Force (F) × time (t)
Force (F) = 5 N
Time (t) = 4×10¯³ s
Change in momentum =?
Change in momentum = 5 × 4×10¯³
Change in momentum = 0.02 Ns
Therefore, the change in the momentum of the ball is 0.02 Ns.
Answer:
Force = 35 N
Explanation:
From Newton's third law of motion, the boy must apply a force greater than the weight of the sled to lift it.
weight of sled = mg
where m is its mass and g the force of gravity on it.
weight of sled = 50 N
Force applied by the boy on the sled = 15 N
Since the force applied on the sled by the boy is lesser than the weight of the sled, then;
Force that the sled exerts on the student = 50 - 15
= 35 N
The force exerted by the sled on the student is 35 N.
