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PtichkaEL [24]
3 years ago
6

I need new friends :(. P.S. STOP MISTAKING ME FOR A BOY!

Mathematics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

sup my guy

Step-by-step explanation:

i can be your friend

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Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0
Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
4 years ago
Y=-x^2+20x-64 what is the max height
Inessa [10]

Answer:

36

Step-by-step explanation:

The maximum height is the y-coordinate of the vertex

given a quadratic in standard form : ax² + bx + c : a ≠ 0

then the x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = - x² + 20x - 64 is in standard form

with a = - 1, b = 20 and c = - 64, hence

x_{vertex} = - \frac{20}{-2} = 10

substitute x = 10 into the equation for y

y = - (10)² + 20(10) - 64 = 36 ← max height


8 0
4 years ago
PLEASE HELP ASAPPPP , Thank you sm .
Montano1993 [528]

Answer: i think 2 feet, not really sure tho ':)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(12) — (23 + 13i) =<br> Chc
rewona [7]

Answer:

-11 - 13i.

Step-by-step explanation:

(12) — (23 + 13i)

= 12 - 23 - 13i

= -11 - 13i.

4 0
3 years ago
5x^2 -15x-140 what method should be use?
elena55 [62]
5x^2 -15x-140

5(x² -(3x) -28)

5(x² +(4x-7x)-28)

5(x(x+4) -7(x+4)

5(x-7)*(x-4)



8 0
3 years ago
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