It is already simplified, three goes into three once but three cant go into 32 without there being a remainder.
Answer:
x= 3
Step-by-step explanation:
19x-5=7+15x
19x-15x=7+5
4x=12
x=12/4
x=3
Recall that A = 1/2bh.
We are given that h = 4+2b
So, putting it all together:
168 = 1/2 b(4+2b)
168 = 1/2(4b + 2b^2)
168 = 2b + b^2
b^2 + 2b - 168 = 0.
Something that multiplies to -168 and adds to 2? There's a trick to this.
Notice 13^2 = 169. So, it's more than likely in the middle of the two numbers we're trying to find. So let's try 12 and 14. Yep. 12 x 14 = 168. So this factors into (b+14)(b-12) So b = -14 or b =12. Is it possible to have a negative length on a base? No. So 12 must be our answer.
Let's check this. If 12 is our base, then according to our problem, 2*12 + 4 would be our height... or 28. so what is 12 * 28 /2?
196. Check.
Hope this helped!
<h3>
Answers:</h3>
- ST = 23
- RU = 8
- SV = 5
- SU = 10
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Explanation:
Focus on triangles SVT and UVT.
They are congruent triangles due to the fact that SV = VU and VT = VT. From there we can use the LL (leg leg) theorem for right triangles to prove them congruent.
Since the triangles are the same, just mirrored, this means ST = UT = 23.
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Following similar reasoning as the previous section, we can prove triangle RVU = triangle RVS.
Therefore, RS = RU = 8
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SV = VU = 5 because RT bisects SU.
Bisect means to cut in half. The two smaller pieces are equal.
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SU = SV + VU = 5+5 = 10
Refer to the segment addition postulate.
i think the answer is 24.56
