3/5 = 6/10 (multiply 2 to top and bottom to get 6/10)
There are 6 1/10ths, so the answer is 6 sections
hope this helps :D
Answer:
(6,-7)
Step-by-step explanation:
subtract them:
-8x - 5y = -13
-4x - 5y = 11
you get
-4x = -24
so x = 6
plug x into the second equation:
-24 - 5y = 11
-5y = 35
y = -7
so your solution is (6,-7).
Answer:
hope it helps you
Step-by-step explanation:
To make such a frequency distribution table, first, write the class intervals in one column. Next, tally the numbers in each category based on the number of times it appears. Finally, write the frequency in the final column. A frequency distribution table drawn above is called a grouped frequency distribution table.
Answer:
Number of calls expected in next week by manager = 7940
Average Number of calls that call center agent will attend in an hour =7 calls
It is also given that, Call center remain open for 10 hours 5 days a week.
Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week ,Part time agents work 20 hours a week but are only on calls 17 hours per week .
⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940
⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940
Option A
⇒35×15×7+17×7×15
= 3675+1785
= 5460
Option B
⇒35 ×7×20+17×7×7
=4900 +833
= 5733
Option C
⇒35×20×7 +17×20×7
=4900+2380
=7280
Option D
⇒25 × 35×7+17×7×5
=6125 +595
=6720
Option E
⇒28×35×7+17×7×10
=6860+1190
=8050
Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.
Answer:
2x - 2y
Step-by-step explanation:
Multiply by 1
combine like terms
Combine the second
rearrange terms
Then you should come up with the sloution 2x - 2y
