Answer:
ба ман нуқтаҳо лозиманд :) умедворам шумо мефаҳмед
Step-by-step explanation:
Answer:
4x²+3x-7 is the answer
Step-by-step explanation:
=(4x²-2x)+(5x-7)
opening brackets
=4x²-2x+5x-7
=4x²+3x-7
i hope this will help you :)
I think you are supposed to find the perimeter of it so you add all sides together to get your answer
Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
D. there is no numbers to work with so you just have to use a variable