Answer:
2/5 hour is closest to 0 1/2 hours, 5/8 hour is closest to 1/2 hour. Therefore, the best estimate for the total time Maria spent with her sister is close to 1 hour
Step-by-step explanation:
We can represent the time Maria spends playing the game as 0.4, since 2/5 as a fraction is 0.4. This is closer to 1/2, which is 0.5 then it is to 0, because 4 is closer to 5 then 0. Then, we can represent the time Maria reads the book as 0.625, which is closer to 1/2 then it is to 1. Now we can add the estimated times. 
hour
Answer:
The probability of Javier volunteers for less than three a month is 25%
Step-by-step explanation:
According to the questions,
The probability of Javier to attend exactly 5 events :-
P ( x = 5 ) = 25% = 
The probability of Javier to attend exactly 4 events :-
P ( x = 4 ) =
The probability of Javier to attend exactly 3 events :-
P ( x = 3 ) =
The probability of Javier to attend exactly 2 events :-
P ( x = 2 ) = 
The probability of Javier to attend exactly 1 events :-
P ( x = 1 ) = 
The probability of Javier to attend no events :-
P ( x = 0 ) =
Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).
P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )
P ( x < 3 ) = 
= 
= = 0.25 = 25 %.
Answer:
10+3pi
Step-by-step explanation:
The perimeter of of the shaded region is
AC+CT+marcSBT+SA
*Finding AC
The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.
*Finding CT
CT=RT-RC where RC is the width of the rectangle
Also RT is a radius so we have that
CT=6-RC
*Finding marcSBT
The circumference of a whole circle is 2pi*r.
We have a quarter of this with r=6.
1/4*2pi(6)
1/4*12pi
3pi
*Finding SA
SA=RS-AR
RS is a radius of the circle and AR is the length of the rectangle.
So we have that this can be rewritten as
SA=6-AR
Let's put these parts together:
6+6-RC+3pi+6-AR
Simplifying:
18-RC-AR+3pi
18-(RC+AR)+3pi
18-8+3pi (Remember length plus width equal 8)
10+3pi
