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Ratling [72]
3 years ago
5

Find 759 ÷ 3. PLS I NEED HELP ITS EITHER HAS A REMAINDER OR NOT ALSO GIVE ME AN ANSWER PLS DIS DUE TODAY

Mathematics
2 answers:
omeli [17]3 years ago
7 0

Answer:

253

Step-by-step explanation:

V125BC [204]3 years ago
7 0

Answer:

yeah 253

Step-by-step explanation:

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Pleaseeee helpppp !!!!!!!! Will mark Brianliest !!!!!!!!!!!!!
Goryan [66]

Answer:

I think you're supposed to add all the fives together. That is what MY teacher taught me to do :/

Step-by-step explanation:

The shape is a square that is tilted and looks like a rhombus. Just add the 5's together.

4 0
2 years ago
An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
The volume of the cube below is 250.047 m^3. The side length could be between which sets of numbers below?
Eva8 [605]

Step-by-step explanation:

The volume of the cube below is 250.047 m^3. The side length could be between which sets of numbers below?

A. 4 cm and 5cm

B 5cm and 6 cm

C. 6 cm and 7 cm

D. 7 cm and 8 cm

ans.C

4 0
2 years ago
What is 1.086 rounded to the nearest whole number
Sphinxa [80]
1.086 rounded to the nearest whole number is 1
5 0
3 years ago
I need help please!!!!
ddd [48]
4^3= 64
2^6= 64

Therefore, n=6.
You can also figure this out if you know that 2^3*2^6=2^9. When you multiply exponents with the same base, add the exponents. 3+6=9

Final answer: n=6
8 0
3 years ago
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