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Ratling [72]
3 years ago
5

Find 759 ÷ 3. PLS I NEED HELP ITS EITHER HAS A REMAINDER OR NOT ALSO GIVE ME AN ANSWER PLS DIS DUE TODAY

Mathematics
2 answers:
omeli [17]3 years ago
7 0

Answer:

253

Step-by-step explanation:

V125BC [204]3 years ago
7 0

Answer:

yeah 253

Step-by-step explanation:

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Which inequality is true?
Vladimir79 [104]

Answer:

C) 3pi>9

Step-by-step explanation:

5 0
3 years ago
6/15=2/c HOW TO SOLVE THIS PROBLEM
Maslowich
The answer is 5. 
you can turn it into a fraction ratio (6 over 15 is equal to 2 over c) and then cross multiply
3 0
3 years ago
Read 2 more answers
The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: T
jasenka [17]

Answer:

For the code we have 3 selections.

The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}

So we have 5 options.

The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)

So here we have 27 - 5 = 22 options

The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.

Here we have 22 - 1 = 21 options.

The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:

C = 5*22*21 = 2310.

There are 2310 different possible codes

8 0
3 years ago
What number is 70% of 120?please give the equation with x
MA_775_DIABLO [31]
You can set up this equation as:
x = 0.7(120)

Because remember, 70% is equal to 0.7 and x represents the unknown value. So, let's just solve it:
x = 0.7(120)=84

So, 70% of 120 is 84.
7 0
3 years ago
Help me please<br>help me please​
Nikolay [14]

Answer:

1 second

Step-by-step explanation:

s=-5\\u=0\\v=\\a=-10\\t=t

\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}

7 0
2 years ago
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