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3 years ago

Which inequality is true A B C D Check picture

Mathematics

2 answers:

Sauron [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Pi is a bit bigger than three(3.141592...) 3x3 = 9, but 3 times anything bigger than it, is more than 9.

Leya [2.2K]3 years ago

3 0

it would be a

Step-by-step explanation:

it would be a because you would have to subtract it

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Select the correct answer.

adoni [48]

The correct answer is b) 2

8 0

4 years ago

Pls help because im awful at math

Vesnalui [34]

Answer:

8/4

Step-by-step explanation:

because 8 is x and x goes first and y is 4 and y goes last

hope this helps!

5 0

3 years ago

Read 2 more answers

olga nikolaevna [1]

Answer:5

Step-by-step explanation:>

Which exponential function is represented by the

graph?

8Hold on, our servers are swamped. Wait for your answer to fully load.

o f(x) = 2( 3 )

O f(x) = {(2Y

o f(x) = {(

(1.1

61,0.25) 17

7605

Of(x) = 2(2)

-5 4 3 2 1

1 2 3 4

6 0

3 years ago

I am just completely lost and am unsure of how to approach this problem.

Ipatiy [6.2K]

Answer:47

Step-by-step explanation: sum of angles in a straight is 180

Aob +Box =180

6x+29+3x+124 =180

9x + 153 = 180

9x =27

x= 3

Boc =6*3 +29

Boc = 47

4 0

3 years ago

Verify that this trigonometric equation is an identity?

Vlada [557]

$\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}$

$=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2$

8 0

4 years ago