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leonid [27]
3 years ago
9

Mathematics question ​

Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer:

it's option B the second one

Klio2033 [76]3 years ago
7 0
The above answer is correct
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The value of y varies directly with x. If x = 2, then y = 10. What is the value of x when y = 100? *​
Fynjy0 [20]

Answer:

20

Step-by-step explanation:

y=kx

X=2 & y= 10

10=2k

k=5

when y=100

100=5x

X=20

8 0
3 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
paula earned a 56% on her science test if she got 14 problems correct then how many questions were on the test
sweet-ann [11.9K]
56% = 14 questions

1% = 14 ÷ 56 = 0.25 questions

100% = 0.25 x 100 = 25 questions

Answer: 25 questions.
3 0
3 years ago
Read 2 more answers
Consider two competing firms in a declining industry that cannot support both firms profitably. Each firm has three possible cho
yaroslaw [1]

Answer:

a) attached below

b)  ( T,T )

c) The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

d) The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 )

Step-by-step explanation:

A) write down the game in matrix form

let: E = exit at the industry immediately

     T = exit at the end of the quarter

     N = exit at the end of the next quarter

matrix is attached below

B) weakly dominated strategies is ( T,T )

C) Find the pure-strategy Nash equilibria

The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

D ) Find the unique mixed-strategy Nash equilibrium

The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 ) since T is weakly dominated then the mixed strategy will be NE

Assume that P is the probability of firm 1 exiting immediately ( E )

and q is the probability of firm 1 staying till next term ( N ) ∴ q = 1 - P.

hence the expected utility of firm 2 choosing E = 0 while the expected utility of choosing N = 4p - 2q .

The expected utilities of E and N to firm 2 =

0 = 4p - 2q = 4p - 2 ( 1-p) = 6p -2 which means : p = 1/3 , q = 2/3

4 0
3 years ago
PLS HELP HURRY ASP BEST ANSWER GETS BRAINLESST!​
a_sh-v [17]

Answer:

Hi there!

The following answers:

3. 7 c > 3 (1/4) pt   4. 5 gal > 18 qt

5. 45 cm = 450 mm 6. 4.5 km < 5000 m

Step-by-step explanation:

There are 2 cups in one pint.

There are 4 quarts in one gallon.

One kilo meter is 1000 meters.

3 0
3 years ago
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