Hello there! How are you today?
5a^2 + 2b^3, solve when a = 4 and b = -4
To solve for this, we must replace "a" with 4, and "b" with -4.
I will set it up;
5(4^2) + 2(-4^3)
Simplify the parenthesis (PEMDAS).
5(16) + 2(-64)
Remove the parenthesis by multiplying them by the numbers to the outside of them.
5 x 16 = 80
2 x -64 = -128
We are now left with:
80 - 128
Simplify.
-48 is your final answer.
I hope this helps!
312016 that is the nearest whole number
Yes because you can multiply 3/4 by 9/9 and you’ll get 27/36 :)
It's A. Move the decimal to the right four places to make one the whole number, and then multiply one by ten to the negative fourth power to write it in scientific notation. If you're given a small decimal, the exponent will be negative. If you're given a large number, the exponent will be positive.
This is what I got putting this into to Desmos. Hope it helps :)