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grin007 [14]
3 years ago
9

Emma bought 7/8 yard of striped ribbon and 8/9 yard of solid ribbon which kind of ribbon did she buy more?

Mathematics
2 answers:
mestny [16]3 years ago
8 0

Answer:

She bought more of the solid ribbon.

Step-by-step explanation:

Let's look for the LCD

The common denominator is 72

So we have 63/72 and 64/72

Thus, 63/72 < 64/72.

astra-53 [7]3 years ago
5 0
7/8 I’m pretty sure
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Tyrone mixed 7/12 quart of red psont with 1/12 quart of yellow paint how much paint does tyrone have in the mixture
Zarrin [17]
Hello there.

<span>Tyrone mixed 7/12 quart of red paint with 1/12 quart of yellow paint how much paint does Tyrone have in the mixture?
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Answer: In this question you need to add together the fractions provided.
The sum would look like this:
</span>\frac{7}{12} + \frac{1}{12} =
<span>Since the denominators are the same , it is simple to add.
All you need to do is 7 + 1 = 8.
Therefore the end result after solving would look like.
</span>\frac{7}{12} + \frac{1}{12} = \frac{8}{12}.
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3 0
3 years ago
Simplify 3+7x-(2+9x)
viva [34]

Answer:

-2x + 1

Step-by-step explanation:

3 + 7x - (2 + 9x)

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3 + 7x - 2 - 9x

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8 0
3 years ago
Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po
jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

Step-by-step explanation:

The given equation is

x^3-21x=-20

It can be written as

x^3+0x^2-21x+20=0

Splitting the middle terms, we get

x^3-x^2+x^2-x-20x+20=0

x^2(x-1)+x(x-1)-20(x-1)=0

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Splitting the middle terms, we get

(x-1)(x^2+5x-4x-20)=0

(x-1)(x(x+5)-4(x+5))=0

(x-1)(x+5)(x-4)=0

Using zero product property, we get

x-1=0\Rightarrow x=1

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Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are \pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20.

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4 years ago
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