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Roman55 [17]
3 years ago
11

Kiaria is 7 years older than Jay. Martha is twice as old as Kiaria. The sum of their three ages is 77. Find the ratio of Jay's a

ge to Kiaria's age to Martha's age. Input note: the parts in your ratio need to add up to 77.
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

The ratio of Jay's age to Kiaria's age to Martha's age.

Jay : Kiaria : Martha

14 : 21 :42

Step-by-step explanation:

Let the ages be represented as:

Kiaria = x

Jay = y

Martha = z

Kiaria is 7 years older than Jay.

x = 7 + y

Making y the subject of the formula

y = x - 7

Martha is twice as old as Kiaria.

z =2x

The sum of their three ages is 77.

x + y + z = 77..... Equation 1

Hence, we substitute in Equation 1

z = 2x

y = x - 7

x + x - 7 + 2x = 77

4x - 7 = 77

4x = 77 + 7

4x = 84

x = 84/4

x = 21

Solving for y

y = x - 7

y = 21 - 7

y = 14

z =2x

z = 2 × 21

z = 42

Hence:

Kiaria = x = 21

Jay = y = 14

Martha = z = 42

The ratio of Jay's age to Kiaria's age to Martha's age.

Jay : Kiaria : Martha

14 : 21 :42

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