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2 years ago

4. See if you can find "like-terms" in the expression and

Mathematics

1 answer:

WITCHER [35]2 years ago

7 0

Answer:

After finding like terms and solving, we get $\mathbf{3x^2+3x+16}$

Step-by-step explanation:

We need to find like terms and simplify the expression $4- 2x + x^2 + 5x + 12 + 2x^2$

Like terms: The terms who have same variable and exponent are called like terms.

So, Combining like terms and solving:

$4- 2x + x^2 + 5x + 12 + 2x^2\\=4+12-2x+5x+x^2+2x^2\\Now \ solving:\\=16+3x+3x^2\\Rearranging \ the \ terms:\\=3x^2+3x+16$

So, after finding like terms and solving, we get $\mathbf{3x^2+3x+16}$

Note: In the question given we have - and + sign with the term 5x i.e 4- 2x + x^2 -+ 5x + 12 + 2x^2

I have solved using +5x, but if the term is -5x then the solution will be:

$4- 2x + x^2 - 5x + 12 + 2x^2\\=4+12-2x-5x+x^2+2x^2\\Now \ solving:\\=16-7x+3x^2\\Rearranging \ the \ terms:\\=3x^2-7x+16$

So, the answer will be: $\mathbf{3x^2-7x+16}$

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A line is drawn so that it passes through the points (-3, -1) and (4, 2).

marishachu [46]

Answer:

(A) $\boxed{\bold{y=\frac{3}{7}x+\frac{2}{7}}}$

(B) $\boxed{\bold{2 \ = \ \frac{3}{7} * \ 4 \ + \ \frac{2}{7} }}$

Explanation:

(A) Slope: y = mx + b

m = 3/7

b = 2/7

Slope = $\bold{\frac{y_2-y_1}{x_2-x_1}}$

$\bold{\left(x_1,\:y_1\right)=\left(-3,\:-1\right),\:\left(x_2,\:y_2\right)=\left(4,\:2\right)}$

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Y intercept

$\bold{y=\frac{3}{7}x+b}$

Plug in $\bold{\left(-3,\:-1\right)\mathrm{:\:}\quad \:x=-3,\:y=-1}$

$\bold{-1=\frac{3}{7}\left(-3\right)+b}$

Isolate B

$\bold{-1=\frac{3}{7}\left(-3\right)+b}$

b = $\bold{\frac{2}{7} }$

(B) 4 = x, 2 = y

2 = 3/7 * 4 + 2/7

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schepotkina [342]

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What is the slope?

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Amanda [17]

Answer:

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Step-by-step explanation:

Data given

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